Circular Motion Lab with Hanging Mass - Trying To Find Centripetal Force

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SUMMARY

The discussion focuses on calculating the centripetal force in a Circular Motion Lab experiment involving a rubber stopper and a hanging mass. The setup includes a 0.4m string with a period of 0.56275 seconds and a hanging mass of 0.03kg. The calculated centripetal velocity is 4.466m/s, and the net force equations are established as Fnet = Ft - Fg and Ft = m(a + g). The tension force (Ft) is calculated to be 0.2943 N, but the discussion highlights the importance of considering the angle of droop in the force diagram for accurate calculations.

PREREQUISITES
  • Understanding of centripetal force and its calculation
  • Knowledge of Newton's laws of motion
  • Familiarity with trigonometric functions (sine and cosine)
  • Basic principles of circular motion dynamics
NEXT STEPS
  • Study the derivation of centripetal force equations in circular motion
  • Learn how to analyze forces in inclined planes using trigonometric functions
  • Explore the relationship between tension, mass, and gravitational force in circular motion
  • Investigate the effects of varying the radius on centripetal force calculations
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Physics students, educators conducting laboratory experiments, and anyone interested in understanding the dynamics of circular motion and force analysis.

albert4united
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Sorry if this is posted in the wrong area, I am relatively new.

Circular Motion Lab is set up like this to study circular motion:

http://docs.google.com/viewer?a=v&q=cache:lG3nvirsnOYJ:www.hwscience.com/Physics/regphysics/Lab%2520Handouts/Circ.%2520motion%2520LAB.pdf+circular+motion+hanging+mass&hl=en&gl=ca&sig=AHIEtbTBHCVNZxCFmkJyfcwpOLkbKJl59w

Rubber stopper is secured to string .4m long, and is spun horizontally and achieves period of 0.56275s. The hanging mass is 0.03kg. The mass of the stopper is unknown.

I figured out that Centripetal velocity is 4.466m/s.

The vertical forces is Fnet = Ft - Fg

Ft= Fnet + Fg
Ft = m(a + g)
Ft= 0.03 (9.81)
Ft= 0.2943

The horizontal forces are Fc = Ft
Fc= 0.2943 N !

Is this done RIGHT to FIND the centripetal FORCE of the rubber STOPPER?
Please explain if I am wrong...
 
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(hint: the radius of the circle made
by the stopper ≠ the length of the string but the angle will cancel out if you do the calculations correctly)

You must consider the angle of droop in your force diagram. Tension is certainly not a vertical force - it is PARTLY vertical and partly horizontal. You'll have sin A and cos A in your expressions when you separate T into horizontal and vertical parts.
circular.jpg
 

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