Circular motion of ball and string question

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In circular motion, a ball on a string experiences centripetal force due to the tension in the string, which acts inward. While there is no real outward force, the ball's inertia causes it to attempt to move in a straight line, creating a sensation of an outward force, often mistakenly referred to as centrifugal force. A free body diagram of the ball shows tension and gravitational force acting on it, with the tension being the only force providing centripetal acceleration. According to Newton's third law, the ball exerts an equal and opposite force on the string, indicating that tension exists in both directions. This dynamic illustrates the balance of forces in circular motion and the importance of understanding inertial frames.
sofiasherwood
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Lets say we have a ball on a string and we spin it around. The ball will undergo circular motion. The tension in the string is what provides the centripetal force, directed inwards. Then what would be the force directed outwards? (According to Newton's third law of motion). It can't be centrifugal, because that is not a real force. Or let's say if we were to draw a free body diagram of the ball, what forces would be present? Assuming there is no tangential acceleration and that the ball is traveling at a constant speed.
 
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The string pulls on the ball, and at the same time the ball pulls on the string. Equal and opposite forces.
 
sofiasherwood said:
Does that mean the ball is also causing tension in the string, pulling it outwards. Just as centripetal force is pulling it inwards. So do we have tension both ways? Or can tension only ever be one way?

Both ways.
See here for more: http://en.wikipedia.org/wiki/Tension_(physics )
 
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According to Newtons first law,the ball tries to move in a straight line.We are constantly changing it's direction.A force is required to change the direction of an object.So a centripetal force is provided.That's it.
 
Hi. The centrifugal force appears in the frame of reference of the ball( which is a non inertial frame). It never arises in the frame of reference of the ground. If we draw a free body diagram of the ball in the ground frame of reference, then the only forces acting on the ball will be the tension (=centripetal force) and gravitational force.Speaking of Newton's third law , you must remember that the equal-and-opposite pair of forces (in general ) will not act on the same body . Here the string exerts an inward force on the ball, and the ball exerts an outward force on the string , both being equal in magnitude. I hope this clears things for you .
 
Let's think for EXAMPLE,you are spinning a ball of mass 100KG(With a very strong rope and a thread.At a certain point,you release the strong rope.The ball will try to move in a straight line at a tangent.As the momentum will be very high,the centripetal force will also be high.The thread can't withstand the force provided,so it breaks.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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