Circular motion of water in a glass

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SUMMARY

The discussion focuses on the dynamics of water in a glass when subjected to circular motion. Participants clarify that the water forms a paraboloid shape due to the balance of centripetal and gravitational forces. The necessary centripetal force is calculated using the formula mv²/R, where m is mass, v is velocity, and R is the radius of the circular path. The conversation also distinguishes between rotating the glass and moving it in orbital motion, which significantly affects the water's behavior.

PREREQUISITES
  • Understanding of centripetal force and gravitational force
  • Familiarity with the concepts of angular velocity and linear velocity
  • Basic knowledge of fluid dynamics and motion in physics
  • Ability to apply mathematical formulas related to motion, such as mv²/R
NEXT STEPS
  • Research the principles of fluid dynamics in circular motion
  • Study the effects of angular velocity on fluid behavior
  • Learn about the mathematical modeling of forces acting on fluids
  • Explore experiments involving rotating systems and their impact on fluid shapes
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Physics students, educators, and anyone interested in fluid dynamics and motion analysis will benefit from this discussion.

mavrick3987
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Hey all,

I'm attempting a lab where I want to have water moving in circular motion in a glass. I realized that the water will climb the side of the glass creating a sort of conical shape, if you will. I know that there is a way to calculate the change in height that occurs as the speed of the water increases. I was thinking centrifugal force, but I don't remember my motion well enough for this sort of thing.

Any and all help would be freakin' awesome:smile:

Aveld
 
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The centripetal force necessary to hold something in a circle of radius R with constant speed v (and so angular speed \omega is mv2/R or m\omega^2R. That vector force, <-mv2/R,0>, added to the gravitational force <0, -mg> gives total force m<-v2/R, -g>, in the xz-plane. More generally, it is m&lt;-(v^2/R)cos(\theta), -(v^2/R)sin(\theta), -g&gt;. It is the &quot;equilibrium&quot; condition, that that vector be perpendicular to the surface of the water that determines its form.
 
As I recall, It forms a paraboloid
 
mavrick3987 said:
Hey all,

I'm attempting a lab where I want to have water moving in circular motion in a glass. I realized that the water will climb the side of the glass creating a sort of conical shape, if you will. I know that there is a way to calculate the change in height that occurs as the speed of the water increases. I was thinking centrifugal force, but I don't remember my motion well enough for this sort of thing.

Any and all help would be freakin' awesome:smile:

Aveld

Are you rotating the glass, or are you moving the glass in orbital motion- moving the glass in a circle without rotating the glass? There's a big difference.
 

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