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- When taking $$ \hbar \rightarrow 0 $$ shouldnt the propagator result in a delta distribution?
I am currently starting with my first qft lectures and i am trying to see for the free particle that the propagator $$ <x_i | e^{-i\frac{p}{2m} T|x_f}>$$ will equal to one if x_f = 1, x_i=0 m=1 u=1 p=1, T=1 and $$\hbar \rightarrow 0$$ or 0 otherwise. I understand that this limit will result in an exponential term, but it is not one.
Any help, explanation why
Any help, explanation why