ClO3+: Hybrid Orbital of Chlorine Atom

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Discussion Overview

The discussion centers on the hybrid orbital of the chlorine atom in the ClO3+ ion, exploring the hybridization state, oxidation state of chlorine, and the Lewis structure representation. Participants are examining the implications of different bonding scenarios and the associated formal charges.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant describes the hybridization of chlorine in ClO3+ as sp2, suggesting that chlorine donates two electrons to two oxygens and loses one electron for the positive charge, resulting in two single bonds and one double bond.
  • Another participant proposes an alternative view where chlorine loses one electron for the positive charge and then uses sp3d hybridization to form three bonds with the oxygens.
  • There is a question regarding the oxidation state of chlorine, with one participant calculating it as +7 based on the assumption that all oxygens have a -2 valence.
  • Concerns are raised about the ambiguity of the oxidation state notation in the book, which could be interpreted as either the overall charge or formal charge.
  • One participant notes that the octet rule is broken in the book's proposed Lewis structure, while they argue that their own structure satisfies the octet rule.
  • A later reply emphasizes the complexity of the concepts involved and suggests comparing formal charges between the book's structure and the proposed structure to clarify understanding.
  • There is a critique of the appropriateness of the question for students new to Lewis structures and hybridization, suggesting it may lead to confusion regarding the extra double bonds and the octet rule violations.

Areas of Agreement / Disagreement

Participants express differing views on the hybridization state of chlorine and the interpretation of the oxidation state. There is no consensus on the preferred Lewis structure or the implications of the octet rule in this context.

Contextual Notes

Participants highlight the potential confusion arising from the book's notation and the complexity of hybridization and formal charge concepts, particularly for those new to the subject. The discussion reflects varying levels of understanding and familiarity with advanced bonding theories.

MarkL
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Decribe the hybrid orbital on the chlorine atom for ClO3+ ion.

The book says sp2 hybrid with double bonds on each O.

But it seems like:
1) Cl should donate 2 electrons to 2 O's
2) lose 1 electron for + charge on ion.
3) form two singles and one double bond with the O's

From this I get sp2 hybrid.

or

1) Cl lose 1 electron for + charge on ion.
2) then sp3d for 3 bonds with O's

Where am I going wrong, please?
 
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What is the oxidation state of Cl in the compound? If you know it draw the electron dot diagram dot for it and start adding oxygens. Assume that all oxygens are at -2 valence.
 
Thank you.

Do you mean oxidation #?

(# for Cl) + 3 x ( -2 for O) = +1 => oxidation # for Cl = +7

Sorry, but you're losing me here. Doesn't Lewis diagram = formal charges?

I just started learning a week ago, so I don't know.

Book says: O::Cl::O ( ion = +1 ) actually, book puts +1 over Cl
::
O ( this goes under Cl )
notice the octet rule is broken

I say: O:Cl:O ( ion = +1 ) octet rule is satisfied
::
O ( this goes under Cl )
 
I am learning form Oxtoby, Chap 16, prob. 19
 
MarkL, given your short exposure to these topics, your proposed structure is perfectly understandable. However there are complex ideas with this ion.

Compare the formal charges for the book's structure vs your proposed structure. Then yes, Lewis structure = formal charge.

IMHO this is not an ideal question to give to students just learning about Lewis structure and hybridization - I think it would have been best left just to ask what the preferred Lewis structure would be (using formal charge) and not ask for the hybridization.

The +1 given in the book's solution is confusing and ambiguous as it can be interpreted as the overall charge or formal charge.
Also it presumes that the student is familiar with why atoms can violate the octet rule in some species.

I'm not familiar with Oxtoby, but the book does give the correct hybridization but leaves the student confused as to how to explain the extra double bonds with the other oxygens. (p-d pi bonding --> I've only seen this discussed in advanced inorganic courses)
 
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