CLYINDRICAL coordinates of volume bound by z=r and z^2+y^2+x^2=4

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Homework Help Overview

The problem involves finding the volume bounded by a cone defined by z = r and a sphere described by z² + y² + x² = 4, using cylindrical coordinates.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the limits for the variable r, with some suggesting it should depend on z, while others propose specific ranges for r and z.

Discussion Status

There is an ongoing exploration of the limits for the integration, with participants providing differing perspectives on how to approach the problem. Guidance has been offered regarding the dependence of r on z.

Contextual Notes

Participants are navigating the constraints of cylindrical coordinates and the specific geometric boundaries defined by the cone and sphere. There are indications of confusion regarding the limits of integration, particularly for r.

Unemployed
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Homework Statement



Find the smaller volume bound by cone z=r and sphere z^2+y^2+x^2=4 using cylindrcal coordinates

Homework Equations



dV=r-dr d-theta dz

The Attempt at a Solution



Limits on r: z to sqrt (4-z^2)
limits on theta: 2pi to 0
limits on z: 2-0

Did this and got 8 pi, not the same answer with spherical.
Need guidance on limits.

 
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Hi Unemployed! :smile:

(have a theta: θ and a pi: π and a square-root: √ and try using the X2 icon just above the Reply box :wink:)
Unemployed said:
Limits on r: z to sqrt (4-z^2)

Not for the cone bit :wink:
 
tiny-tim said:
Hi Unemployed! :smile:

(have a theta: θ and a pi: π and a square-root: √ and try using the X2 icon just above the Reply box :wink:)


Not for the cone bit :wink:


For r = 0 to √2 ?
 
No, the limit for r will still depend on z, but linearly instead of "curvily". :wink:
 

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