KingGambit said:
Dear PF Forum,
What is CNO Cycle?
Is it Carbon Nitrogen Oxygen cycle or Carbon Neon Oxygen?
In this video, Derek Muller says that Carbon fuses into Neon, and Neon fuses into Oxygen.
I can't imagine that Derek makes an error here. But for myself, I get a little confused, too.
If Carbon is bombarded by Alpha particle, then Carbon should become Oxygen, right. And Oxygen + Alpha particle = Neon?
Unless proton/s are expelled on reaction with alpha particle!
KingGambit said:
So, can I ask what fusion happens in a star start from Carbon,
Is it Carbon, Nitrogen, Oxygen
- if this is, then what element that Carbon fuses to, to become Nitrogen, it can't be Alpha particle, right.
One option of fusion cycle. That is fusion with protium. (Note that deuterium and tritium are rare in stars, deuterium because it rapidly fuses with protium).
While wikipedia CNO cycle article is nice, it does not address the branching well, by treating CNO as separate cycles.
Have a look at
https://www-nds.iaea.org/relnsd/vcharthtml/VChartHTML.html. Hover the mouse cursor at an isotope, and it shows a number of ways to break up the nucleus.
Look at
13N. It shows:
...
Q
α=-9495 keV (and more digits I´m truncating out)
...
S
p=1943 keV
This means that there are the following "possible" reactions:
13N=
12C+p-1943 keV
13N=
9B+α-9495 keV
Note that S is (almost) always expressed as positive, it is the energy lost knocking out a nucleon or gained adding it (
9B is one of the few exceptions - it immediately fissions to p+2α). Q may be positive or negative, if it is negative then the decay cannot happen unless energy is added.
So we see that reaction
12C+p=
13N+γ
is possible.
Reaction
13N=9B+α=3α+p
will happen only if a huge amount of energy is somehow supplied. I marked it in italics that it is the ruled out alternative.
Continuing the chain...
13N will emit positron or capture electron to promptly convert to
13C. I'll imply these beta decays for all radioactive isotopes in the chain/cycle.
13C+p=
14N+γ+7550 keV
14N=10B+α-11612 keV
next:
14N+p=
15O+γ+7296 keV
15O=11C+α-10218 keV
But:
15N+p=
16O+γ+12127 keV
16O=12C+α-7161 keV
summing up to:
15N+p=12C+α+4966 keV
This I bolded because in contrast to previous 3 reaction pairs, this time adding proton to get
16O releases more energy than is needed to take α out and therefore this last reaction is possible.
A general rule is that when the same reagents of nuclear reaction can form either one nucleus and a gamma ray OR two nuclei then forming two nuclei happens much more often even though it releases less energy. This is why it is named STRONG interaction!
The bolded interaction closes one cycle. The reaction forming
16O is the minor branch.
What next?
16O+p=
17F+γ+600 keV
17F=13N+α-5818 keV
next
17O+p=
18F+γ+5607 keV
18F=14N+α-4415 keV
17O+p=14N+α+1192 keV
This closes cycle, again! And it returns to the middle of the previous cycle! If you heat any of the
15O,
16O or
17O with hydrogen, the oxygen is mainly destroyed, forming helium and carbon, or first helium and nitrogen (and then converting carbon to nitrogen and back - but NOT converting them to boron).
But the second cycle again has the minor exit forming
18F. What next?
18O+p=
19F+γ+7993 keV
19F=15N+α-4013 keV
18O+p=15N+α+3980 keV
Third return of the loop, and also to the middle of the first cycle! All stable O isotopes are destroyed on heating with hydrogen.
Next:
19F+p=
20Ne+γ+12843 keV
20Ne=16O+α-4729 keV
19F+p=16O+α+8114 keV
fourth return of the loop
the minor exit
20Ne+p=
21Na+γ+2431 keV
21Na=17F+α-6561 keV
next
21Ne+p=
22Na+γ+6738 keV
22Na=18F+α-8479 keV
next
22Ne+p=
23Na+γ+8794 keV
23Na=19F+α-10467 keV
next
23Na+p=
24Mg+γ+11692 keV
24Mg=20Ne+α-9316 keV
23Na+p=20Ne+α+2676 keV
And this is a new loop! It does NOT loop back to the previous loops - heating Ne and Na with hydrogen can convert them to each other, but can NOT convert them to F, and then back to C, N and O. This is why there is a CNO cycle that ends after F.
However, it is very hard to remove CNO from CNO cycle. In order to convert CNO into Ne, the reaction has to take the less likely branch 4 times in a row. Which is why CNO mostly cycle between each other, and don´t produce much Ne.