Coefficent of Friction Question

  • Thread starter UFGators35
  • Start date
  • #1

Homework Statement



A 1200 kg car traveling at 13 m/s is able to skid to a stop over a distance of 30 meters. What must be the coefficient of friction between the road and the tires for this to be possible?

m= 1200kg
Vo= 13 m/s
V= 0 m/s
x= 30 m


Homework Equations



I think this is kinetic friction so:

fk=µkFn


The Attempt at a Solution



I know I want to solve for µk but we haven't been over this in class and I am not really sure how to solve for it. I also don't know how I arrive at fk and Fn from the info I was given.
 

Answers and Replies

  • #2
hage567
Homework Helper
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Do you know how to find the acceleration given the info in the question?

Do you know what the normal force is?

Do you know Newton's second law?
 
  • #3
The acceleration:
V^2x= Vo^2x + 2ax(x)
a= -Vo^2x / 2x
a= -169 / 60
a= -2.8166667 m/s^2

Normal Force:
ΣF=ma
ΣF= 1200 * -2.8166667
ΣF= -3380 N
 
  • #4
hage567
Homework Helper
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2
Your first part for the acceleration is right. But the normal force is not what you have in the second part. The normal force is the reaction force of the car on the road. It acts perpendicular to the surface of the road, and has a magnitude of Fn = mg. You need to put that into your equation for the frictional force that you have in your first post. Since you know m, g and have found m*a, you can solve for [tex]\mu_k[/tex].
 

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