# Coefficient of maximum static friction

1. Oct 11, 2008

### xmflea

this is a lab that i've been working on for 3 days alredy, and still cannot fill in the blanks for finding the coefficient of maximum static friction...

a wooden block was attatched to a pulley connected to a hanger.. the wooden block was on top of a wooden board.. the goal was to add just enough weight to the hanger to make the wooden block slide... the wooden block was sliding horizontally.

for one of my results... the mass of my wooden block was 0.543kg..the mass on the hanger required to move the block was 0.170kg... now i calculated the weight of the block to be 5.32N, and the weight of the hanger to be 1.67N....
now i am asked to find the coefficient of the maximum static friction... and ive tried everything for three days. multiplying and dividing up and down etc... the only equation given is Fs is less than or equal to UsN (U=mu you know that greek symbol). and they want me to find Usmax with that equation. my Lab TA has extremely broken english and when he explains he just expects me to know what he means. the lab instructor is just at the school for research and is never around to care about helping students. a friend of mine told me to find the normal force, which i tried doing by adding the two masses and multiplying by 9.8. but i dont know where to go from there.

2. Oct 11, 2008

### Staff: Mentor

Let's start by getting some terminology straightened out. μs is the coefficient of static friction. The maximum value of static friction is given by Fs = μsN. There's no coefficient of "maximum" static friction.
That's the only equation you need.

Here's the idea. You keep piling weight on the hanger, which pulls the block via tension in the string, but the opposing static friction is enough to prevent any motion. But when you put just enough weight on the hanger, and the tension just barely exceeds the maximum value of static friction, the block just starts to move. That's when you can apply that equation. What's the normal force on the block? What must the friction force equal?

3. Oct 11, 2008

### xmflea

so the normal force on the block is 5.73N. so would the equation look like.

5.73N= μs1.67 ? and then i solve for us?

4. Oct 11, 2008

### Staff: Mentor

Yes, except how did you get 5.73 N?

Edit: You have the normal force and the friction force mixed up.

Last edited: Oct 11, 2008
5. Oct 11, 2008

### xmflea

5.73N is the weight of the block on the board it was found by multiplying 0.543 by 9.8.

6. Oct 11, 2008

### Staff: Mentor

Redo that calculation.

7. Oct 11, 2008

### xmflea

so the coeficcient of maximum static friction is 3.186? μsmax = 3.186?
that number seems large

8. Oct 11, 2008

### Staff: Mentor

Yeah, it's way off. You had the equation backwards (I mustn't have been paying attention earlier :uhh:):
You have the normal force and the friction force mixed up.

9. Oct 11, 2008

### xmflea

so its the other way around.. i got usmax=0.314

10. Oct 11, 2008

### Staff: Mentor

Good. But don't call it usmax, it's just us.

11. Oct 11, 2008

### xmflea

well the lab calls it usmax, but i got ya , thanks a lot.

12. Oct 11, 2008

### Staff: Mentor

Then you'd better use their terminology, even though it makes no sense!

And you're welcome.