1. The problem statement, all variables and given/known data A uniform 7.7 m tall aluminum ladder is leaning against a friction-less vertical wall. The ladder has a weight of 291 N. The ladder slips when it makes a 59.0◦ angle with the horizontal ﬂoor. Determine the coeﬃcient of static friction between the ladder and the ﬂoor. 2. Relevant equations τ = (r) (F) (sin(Θ)) r = (1/2)(h) (because it is a solid figure and force applies from the center of it) τx = τ cos(Θ) F(friction max) = µs * N (so) µ(static) = F(friction max) / N 3. The attempt at a solution h = 7.7 M=291 Θ=59◦ r = 3.85 so: τ = (3.85) (291) (sin(59◦)) τ = 960.3274 τx = 960.3247 * cos(59◦) τx = 494.6052 so if τ(x) is the amount of force moving in the x direction, then shouldn't τx = Force(friction max) ? µs = F(friction max) / N µs = 494.6052 / 291 which is more than 1 so it is obviously wrong. I am clearly going in the wrong direction and I would really appreciate any help that you could offer, even if you tell me i need to scrap this! If you could steer me in the right direction I would greatly appreciate it!