"Collision Homework: Find Mass of Cart & Impact Force

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SUMMARY

The discussion centers on a physics homework problem involving a cart and a child colliding. The cart has an initial velocity of 2 m/s and is reduced to 1 m/s after the child, with a mass of 2 kg, jumps onto it at a 60º angle. Using the conservation of momentum, the mass of the cart is calculated to be 14.64 kg. The second part of the problem seeks to determine the impact force perpendicular to the tracks, but the user is uncertain about which mass to use and lacks the time variable for calculations.

PREREQUISITES
  • Understanding of conservation of momentum
  • Familiarity with basic physics equations: p = mv and F = ma
  • Knowledge of vector components in physics
  • Ability to solve problems involving collisions and forces
NEXT STEPS
  • Review the principles of conservation of momentum in collisions
  • Learn how to calculate impact force using the formula F(impact) = m(Δv/Δt)
  • Study vector decomposition to analyze motion at angles
  • Explore examples of collision problems in physics textbooks or online resources
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and collision problems, as well as educators looking for examples of momentum conservation and impact force calculations.

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Homework Statement



A cart is driving on straight tracks with a velocity of 2 m/s. In the opposite direction, with an angle of 60º according to the tracks, a child with a mass of 2 kg is running with a velocity of 2m/s, he jumps on the cart and stays there.
- Find the mass of the cart, if its velocity is reduced to 1 m/s when the child jumps onto it.
- What is the impact force perpendicular to the tracks?

http://www.slide.com/s/QOXg7ix_pD-d7WoZA5-k0knIny1R-ZsX?referrer=hlnk

Homework Equations



p= mv
F= ma

The Attempt at a Solution



First part: Find the mass of the cart, if its velocity is reduced to 1 m/s when the child jumps onto it.

Conservation of the moment:

m(2)= 20 kg, v(1-initial)= v(2-initial)= 2 m/s, v(3)= 1 m/s, θ= 60º

m(1)v(1) + m(2)v(2)sinθ= (m(1) + m(2))v(3)
2m(1) + 34.64= m(1) + 20
m(1)= 14.64 kg

Are my calculations correct?

Second part: What is the impact force perpendicular to the tracks?

For this part, I know that the formula for impact force is F(impact)=m(Δv/Δt), but I don't know which mass to use and I don't have the time (t).
Any hint what I should do, or is there another equation to find the impact force without knowing the time (t)?

Thank you for helping!
 
Last edited by a moderator:
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Can someone, please, take a look at this problem!
Thank you!
 

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