Collision Investigation Problem (2-D Linear Momentum, etc.)

  • Thread starter Gin-Su
  • Start date
  • #1
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My class was given a packet with several scenario questions. I've got the rest of them completed and this is the only one remaining.

So I know that the question involves: Momentum Conservation (2-D): Inelastic collisions, Work-energy: Conservation of energy with friction, Dynamics: Newton's Second Law, frictional force, Kinematics: 1-D and 2-D

Homework Statement


(This is a really long question, I apologize in advance.)

This is a scenario based question where I role play as an intern for the Montreal Police Collision Investigation Unit. Basically I have to determine the initial velocity of vehicles to determine whether or not they are liable under Section 249 (3) of the Criminal Code, meaning if they are going over 30 km/hr over the limit, they face charges.

Now for the data:
  • Debris was found at a distance of 12.63 m from the red vehicle. (I am sure that this is data thrown in to distract)
  • Debris was also found 11.87 m from the yellow vehicle. (I am also sure that this is unneeded.)
  • The yellow vehicle braked in a straight line.
  • The red vehicle veered 6.5º from its initial course.
  • The marks of the impact on the red vehicle show that it was heading 98º away from the yellow vehicle at the moment of collision.
  • Prior the point of collision, there are skid marks over a distance of 30m.
  • The speed limit is 70 km/hr.
  • Mass of vehicle 1 (yellow) 2674 kg
  • Mass of vehicle 2 (red) 1110 kg
The velocity indicators provided were:
Velocity indicators are defined as follows:
  • V1IB: velocity of vehicle 1 before initial braking
  • V1B : velocity of vehicle 1 just before impact
  • V2B : velocity of vehicle 2 just before impact
  • V1A: velocity of vehicle 1 just after impact
  • V2A: velocity of vehicle 2 just after impact
Friction Data:
Mass of friction block: 9 kg
Ftension = 75.8 N
(I apologize in advance for including a picture; however I felt that it would aid in visualizing the scene.)
oCoYtPF.png

Homework Equations



Fkk(Fn)
Fnet=ma
(1/2)v1o2+(1/2)v2o2=(1/2)v1f2+(1/2)v2f2
Pox=Pfx
m1v1o-m2v2o=m1v1fcosθ1+m2v2fcosθ2
Poy=Pfy
m1v1o-m2v2o=m1v1fsinθ1+m2v2fsinθ2]
(Others maybe?)

The Attempt at a Solution



I actually did this initially in a completely different way using Vf2=Vo2+2(a)(Δx), which I now realize is completely wrong. (I ended up getting 95.65 hm/hr for the driver in V1, which doesn't mean anything since I am wrong.)

This was my second attempt:

75.8N=μk(88.2N)
μk=.86

Fnet=ma
kmg=ma
-.86(9.8)=a
-8.428 m/s2=a

This is where I have some trouble, as I am not sure where I would proceed. The angles are throwing me into a bout of confusion as this is the first time I am facing a problem like this.

(1/2)v1o2+(1/2)v2o2=(1/2)v1f2+(1/2)v2f2

So I think I should then use the x and y components.

Pox=Pfx
m1v1o-m2v2o=m1v1fcosθ1+m2v2fcosθ2

2674(v1o)-1110(v2o)=2674(v1f)cos(0)+1110(v2f)cos(6.5)
(I am not 100% sure I should be using 6.5°.)

2674(v1o)-1110(v2o)=2674(v1f)+1110(v2f)cos(6.5)

This is the point at which I am stuck. I am not sure if it's because I am using the wrong equations or if it's because I am overlooking something.

Thank you for taking the time to read this. Any help would be greatly appreciated.
 

Answers and Replies

  • #2
lightgrav
Homework Helper
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debris is found all over the place implies that KE is not conserved during the collision
(it is almost perfectly inelastic since the skid marks after collision are almost same length)
but momentum is conserved.
I would run the calculation forward, using the limiting initial velocity for big yellow (100km/hr)
part A: v² formula with skid
part B: inelastic collision; using the 8° impact angle means the red velocity x-component is very small
part C: v² formula with skid ... can the yellow stop in that skid distance? if no, they were over the limit.
 
  • #3
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Thank you for steering me in the right direction.
 
  • #4
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I apologize for the double-posting, but I am currently stuck on part b of what you recommended.

2674(16.307)-1110(vv2i) = (2674)(vf1)cos(0°)+(1110)(vf2)cos(98°)
2674(16.307)-1110(vv2i) = (1110)(vf2)sin(98°)

How could I solve for the multiple variables. I tried solving for one and inputting it into the other equation; however that's not getting me anywhere.
 
Last edited:
  • #5
haruspex
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Several inconsistencies between diagram and text:
The velocity labels are different (v1A, v1B etc.). The confusion is compounded by then inventing different labels in the working: v1f, v2f. Please define one set of labels, each unique, and stick to them.
the red vehicle ... was heading 98º away from the yellow vehicle
Not according to the picture.
The red vehicle veered 6.5º from its initial course.
Not according to the picture.

Work backwards from the end. Find the two velocities just after collision.
It looks like the yellow car maintained its direction. What does that tell you about the change in the red vehicle's momentum caused by the collision?
 
  • #6
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Several inconsistencies between diagram and text:
The velocity labels are different (v1A, v1B etc.). The confusion is compounded by then inventing different labels in the working: v1f, v2f. Please define one set of labels, each unique, and stick to them.

Not according to the picture.

Not according to the picture.

Work backwards from the end. Find the two velocities just after collision.
It looks like the yellow car maintained its direction. What does that tell you about the change in the red vehicle's momentum caused by the collision?

Yeah I apologize for that. I noticed the inconsistency when I was typing it up to. The labels were given to me, so I automatically included it. I apologize for that oversight. The photo was also included by default in the assignment.

I took your advice and worked on it backwards and I think I have the solution. Thank you for your help.
 
  • #7
haruspex
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I took your advice and worked on it backwards and I think I have the solution.
Good show.
 
  • #8
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How would you find the velocities right after the collision?
 
  • #9
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Several inconsistencies between diagram and text:
The velocity labels are different (v1A, v1B etc.). The confusion is compounded by then inventing different labels in the working: v1f, v2f. Please define one set of labels, each unique, and stick to them.

Not according to the picture.

Not according to the picture.

Work backwards from the end. Find the two velocities just after collision.
It looks like the yellow car maintained its direction. What does that tell you about the change in the red vehicle's momentum caused by the collision?
How would you find the velocities right after the collision?
 
  • #10
haruspex
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How would you find the velocities right after the collision?
From the friction data, you know the deceleration. From the debris data, you know the distance to come to a stop. From those you can determine the velocity just after collision.
 

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