1. The problem statement, all variables and given/known data The lens and mirror in the figure below have focal lengths of +74.0 cm and -59.1 cm, respectively. An object is placed 1.00 m to the left of the lens as shown. http://www.jmlproductions.net/jmlproductions/p36-54.gif [Broken] I need to find the final image location. 2. Relevant equations This problem uses the lens equation: 1/p + 1/q = 1/f For verification, I use the equations M = -q/p and Mf = M1M2 as the second part asks for final magnification. 3. The attempt at a solution I have tried this a few times. Calculate the image position for the first lens: 1/100 + 1/q = 1/74 1/((1/74)-(1/100)) = q So q = 284.62 cm, so the distance of p for the mirror then is -q+100, which means that it's behind the mirror with p = -184.62 cm. Using the lens equation again: 1/-184.62 + 1/q = 1/-59.1 1/((1/-59.1)+(1/184.62)) = q q = -86.93, so the image is formed in front of the mirror (? convex mirror? Should this happen?) To convert q to p for the first lens again, add 100 and multiply by -1. p = -13.07 Then find the final image position. 1/-13.07 + 1/q = 1/74 1/((1/74)+(1/13.7)) = q q = 11.1 So add this to 100 to get final position at 111.1 cm I have not actually submitted this answer, but using those numbers to calculate the final magnification, it is also incorrect as the magnification is wrong. What I do know is that the final image is inverted. Many thanks to those that help.