Combinations possible when choosing 4 or 5 team members from

Click For Summary
The discussion focuses on calculating the number of combinations when selecting 4 or 5 members from a group of 10. The binomial coefficient is used, with binomial(10,4) and binomial(10,6) both equaling 210, while binomial(10,5) equals 126. A point of confusion arises regarding the need to divide the combinations by 2 when selecting 5 members, which is clarified by considering whether the groups are treated as distinct or equivalent. If the groups are considered equivalent, dividing by 2 is necessary; otherwise, they remain distinct. The conversation emphasizes the importance of understanding how group distinctions affect combination calculations.
zimbabwe
Messages
33
Reaction score
0

Homework Statement


How many combinations of people are there if you choose 4 or 5 from a group of 10?

Homework Equations


Relies on binomials

The Attempt at a Solution


binomial (10,4) = binomial (10,6) = 210
But when choosing 5 the answer is binomial (10,5) / 2 = 126
Why do I need to divide by 2?
 
Physics news on Phys.org
I am not sure. Is the question to have 10 people, and sometimes you might choose 4 or maybe you choose 5? Then find the total number of combinations.
Could you just have an 11th "person" (person0) which means nobody, then choose 5 from 11? Sometimes one of the five "people" would be nobody, so you would just have 4 people.
 
This depends on what divisions of "groups of 5" you consider equivalent. If it does not matter which group of 5 you end up in abcde|fghij is the same division as fghij|abcde. You do not have this issue in the case of splitting into one group of 4 and one of 6. However, if it does matter which group is which (e.g., all people in the first group gets a lollipop and the others do not) then those two divisions would be different and you would not divide by two.
 
  • Like
Likes scottdave
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
1K