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Precalculus Mathematics Homework Help
How Many Ways to Deal Two Distinct Pairs in a Four-Card Hand?
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[QUOTE="davedave, post: 5472778, member: 120584"] [h2]Homework Statement [/h2] 4 cards are dealt from a 52-card deck. How many hands contain 2 distinct pairs? [h2]Homework Equations[/h2] This is an expression I come up with 13C1x4C2x12C1x4C2. [h2]The Attempt at a Solution[/h2] This is how I approach it. From the 13 ranks, I choose 1. In this rank, I choose 2 cards from 4. From the remaining 12 ranks, I choose 1. In this rank, I choose 2 cards from 4. Now, I do the following calculations with combinations. 13C1x4C2x12C1x4C2 = 5616. My neighbor told me that it's wrong. He didn't explain why it was wrong. I cannot find any mistakes. Please explain what I have done wrong. Thank you very much. [/QUOTE]
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How Many Ways to Deal Two Distinct Pairs in a Four-Card Hand?
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