Combining Sine and Cosine Functions for f-g: Homework Example

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To express the function y = sqrt2sin(pi(x-2.25)) in the form of f-g, where f is a sine function and g is a cosine function, it is essential to use the identity sin(a - b) = sin(a)cos(b) - cos(a)sin(b). By substituting a = pi*x and b = 2.25*pi, the equation can be rewritten to isolate the sine and cosine components. The constants A, B, w, and v need to be determined from this transformation. The discussion highlights confusion regarding how to derive the specific forms of f(x) and g(x) from the given equation. Understanding this identity is crucial for finding the correct functions.
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Homework Statement


Determine a sine function, f, and a cosine function, g, such that y = sqrt2sin(pi(x-2.25))
can be written in the form of f-g.

Homework Equations


(f-g)(x) = f(x) - g(x)

The Attempt at a Solution


I think that you should sub in the y= equation so that you get:
sqrt2sin(pi(x-2.25)) = f(x) - g(x)

and then sub in any X value? I really don';t know
 
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Do you understand what the question is asking? You are to find a function f(x)= A sin(wx) and a function g(x)= B cos(vx) for constants A, B, w, and v. Since you don't yet know what f and g are, putting values of x into what you have won't tell you anything.

What you need is the identity sin(a- b)= sin(a)cos(b)- cos(a)sin(b). That way, sin(pi(x- 2.25)= sin(pix- 2.25pi)= sin(pix)cos(2.25pi)- cos(pix)sin(2.25pi), a constant times a sine function of x and a constant times a cosine function of x.
 
Sorry for my ignorance, I understand what you explained previously, but I don't understand what I get for f(x) and g(x)?
 

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