Show that the T is a linear transformation

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
10 replies · 2K views
Dank2
Messages
213
Reaction score
4

Homework Statement



T:R2[x] --> R4[x]
T(f(x)) = (x^3-x)f(x^2)

Homework Equations

The Attempt at a Solution


Let f(x) and g(x) be two functions in R2[x].
T(f(x) + g(x)) = T(f+g(x)) = (x^3-x)(f+g)(x^2) = (x^3-x)f(x^2) + (x^3-x)g(x^2) = T(f(x)) + T(g(x)).
let a be scalar in R:
aT(f(x)) = a(x^3-x)f(x^2) = (x^3-x)af(x^2) = T(af(x)).
 
Physics news on Phys.org
Dank2 said:

Homework Statement



T:R2[x] --> R4[x]
T(f(x)) = (x^3-x)f(x^2)

Homework Equations

The Attempt at a Solution


Let f(x) and g(x) be two functions in R2[x].
T(f(x) + g(x)) = T(f+g(x)) = (x^3-x)(f+g)(x^2) = (x^3-x)f(x^2) + (x^3-x)g(x^2) = T(f(x)) + T(g(x)).
let a be scalar in R:
aT(f(x)) = a(x^3-x)f(x^2) = (x^3-x)af(x^2) = T(af(x)).

So, what is your question for us?
 
Ray Vickson said:
So, what is your question for us?
Title, to show that T is linear transformation, what i did is enough?
 
Dank2 said:
Title, to show that T is linear transformation, what i did is enough?

I suggest you try to answer that for yourself. Ask yourself: have you verified all the required properties that a linear transformation would have? If you are unsure, then ask yourself which properties you think you have missed.
 
These are the two properties that is required, but the way that it's shown, since it's with a function, is correct?
 
Dank2 said:

Homework Statement



T:R2[x] --> R4[x]
What are R2[x] and R4[x]?
Are these polynomials with real coefficients of degree less than 2 and 4, respectively?
 
  • Like
Likes   Reactions: Dank2
Mark44 said:
What are R2[x] and R4[x]?
Are these polynomials with real coefficients of degree less than 2 and 4, respectively?
that's correct.
 
Mark44 said:
What are R2[x] and R4[x]?
Are these polynomials with real coefficients of degree less than 2 and 4, respectively?
I have been told now it should be R6[x].

How can i see that it's right?, that's it R6[x] and not R4[x] or i can't see it and it depends on f(x) and it's pre-defined?
 
Last edited:
Dank2 said:
I have been told now it should be R6[x].
Who told you that?
Since ##f \in R_2[x]##, then f(x) = ax +b, right? According to the formula you posted, what is T[f(x)]?
Dank2 said:
How can i see that it's right?, that's it R6[x] and not R4[x] or i can't see it and it depends on f(x) and it's pre-defined?
 
Mark44 said:
f∈R2[x]
Forgot about that simple fact.

T(f(x)) = T(ax+b)= (x3-x)*(ax2+b) , which is really a polynomial of degree 5 , so the image of transformation is indeed at R6[x] - All the polynomial of degree 5 or less.3
Mark44 said:
Who told you that?
class teacher.
 
Last edited:
I got confused since different textbooks describe spaces like R6[x] as "polynomials of degree less than 6" and others describe the as "polynomials of degree less than or equal to 6." Also, the notation I've seen many times is p2[x] to mean the same as your R2[x].

The work you did in the first post seems OK to me, but I think the intent of the problem is that you should show how things work with the specific spaces that are given. It should be easy to show that T[f + g] = T[f] + T[g] and that T[af] = aT[f], but I believe they want you to use generic functions in R2[x].