Combining Proportionality Statements

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Combining proportionality statements "a ∝ b" and "a ∝ c" leads to the conclusion that a can be expressed as a product of constants and the variables, specifically a = kbc, where k is a constant. The discussion highlights the confusion around the nature of constants of proportionality when one variable is held constant while considering the relationships between the others. It emphasizes that the constants of proportionality can incorporate other variables when they are held constant. The conversation also touches on the implications of these relationships in mathematical reasoning and how they relate to scientific principles. Ultimately, the exploration reveals the complexity of defining constants in the context of proportional relationships.
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If you have two statements, "a ∝ b" and "a ∝ c", you would get: "a = xb" and "a = yc" (where x and y are the constants of proportionality)

But what do you do so that it turns out to be "a = b × c"?

I've been searching for a DETAILED MATHEMATICAL explanation but have failed in finding one that responds thoroughly to my inquiry. I mean, I understand how it would result in "a = bc", but I'm having trouble understanding how to get there in concise mathematical steps and easy-to-understand mathematical reasoning.
 
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If anything, I would intuitively think that "a ∝ b" and "a ∝ c" imply "a ∝ bc", and thus a = kbc, where k is a constant of proportionality.

EDIT:
Actually, I'm wrong.

First, some definitions:
-to say of two variables a and b that "a ∝ b" means there exists a nonzero real constant k such that a = kb

"a ∝ b" and "a ∝ c" imply a = bk and a = jc for some nonzero k, j in R, respectively.
Then bc = (a/k)(a/j) = a2/(kj) and so a2 = (kj)bc, where (kj) is the product of two arbitrary constants in R and is thus itself an arbitrary constant in R. Therefore a2 ∝ bc.

EDIT 2: And in fact, a = bc would imply that a2 = (kj)bc = (kj)a, implying a = kj = constant. But a is a variable!
 
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This may be a quibble, but a=b x c means a ~ b where c is constant and a ~ c where b is constant.
 
Hmm. Is there no way to prove that "k = c" and "j = b" though?
 
mathman said:
This may be a quibble, but a=b x c means a ~ b where c is constant and a ~ c where b is constant.

I've been thinking about this and somehow it managed to clear things up a lot haha. Thank you.

But now there's something bothering me about this description; if you hold one variable constant, how can you say that that same variable is the constant of proportionality?

Looking at this now, this seems more of a general science question than it is a math question...

EDIT: What I mean is that given this description of what proportionality statements signify about dependent and independent/constant variables, do we just ASSIGN the constant variables to constants of proportionalities?
 
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mathman said:
This may be a quibble, but a=b x c means a ~ b where c is constant and a ~ c where b is constant.

Yes, sorry, I should have included that as well.

Here's something I found though that explains the procedure a bit better (page 243, #389). What I don't understand though is why the two cases are taken consecutively (ie. the author goes from \frac{A}{a'} to \frac{a'}{a}). Is this the only way to reason this without paying attention to what the proportionality constants are dependent on?
 
Saying "a ∝ b" means a= kb (k constant) all other factors held constant. saying "a ∝ c" means a= hc (h constant) all other factors held contstant. That tells you that the "k" in a= kb includes c as a factor (which is being held constant) and that the "h" in a= hc includes b as a factor (which is being held contstant). The two together tell you that a= jbc where j is a constant (as long as all other factors are held constant.
 

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