Commutate relation of lowering operator and sperical tensor operators

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SUMMARY

The discussion centers on the commutation relation between the lowering operator (J-) and spherical tensor operators (Tkq) as presented in Shankar's "Quantum Mechanics" (2nd edition, page 418, Eq 15.3.11). The relation is given by [J-, Tkq] = -ħ√((k+q)(k-q+1)) Tkq-1. The presence of the negative sign in this equation is attributed to the convention used for the T operators, which can vary. Different sources, such as Messiah's "Quantum Mechanics" (Vol II, page 572, Eq XIII.123a), present variations of this relation without the negative sign, indicating that both forms are correct depending on the adopted convention.

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Einsling
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Hi all,

I found a commutation relation of lowering operator(J-) and spherical operator in Shankar's QM (2ed, page 418, Eq 15.3.11):
[J_-,T_k^q] = - \hbar \sqrt{(k+q)(k-q+1)} T_k^{q-1}

I wonder how the minus sign in the beginning of the right hand side come out?

I have googled some pages, some of them have that "-", e.g. :
http://galileo.phys.virginia.edu/classes/752.mf1i.spring03/TensorOperators.htm
the formula appears at the end of this page.

and some has no "-", e.g.:
http://atoms.vuse.vanderbilt.edu/Elements/CompMeth/HF/node30.html
Eq(116) at the beginning .

I also found there's no minus in Messiah's QM (Vol II, page 572, Eq XIII.123a)
[J_-,T_q^{(k)}] = \sqrt{k(k+1)-q(q-1)} T_{q-1}^{(k)}


So, the question is which one is correct?

Thanks :)
 
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Both are correct. It depends on the convention adopted for the T operators. In particular, for a vector operator, it depends on whether T^{\pm 1}_1 = x\pm iy or T^{\pm 1}_1 = \pm(x\pm iy).
 
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