Commuting observables for Fermion fields?

In summary, the conversation discusses the concept of choosing a complete set of commuting observables to describe the Hilbert space in nonrelativistic QM and free boson fields. However, this approach does not work for fermion fields due to the given anticommutation relations. It is suggested that a possible direction for defining a complete set of commuting observables for a fermion field, such as a free Dirac field, could be quadratic expressions in the fermion fields. However, due to the fields being distribution-valued, this is considered an ill-defined problem. It is also mentioned that if space is discretized, it is possible to diagonalize each qubit separately and take a continuum limit. This could potentially lead to operators with
  • #1
maline
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In nonrelativistic QM, we usually describe the Hilbert space by choosing a complete set of commuting observables, so that the set of states that are eigenstates of all the observables can be used as a basis. For instance, the "wavefunction" is the state as expressed in terms of "states" with definite positions for all particles (not normalizable, but that can be dealt with), which works because the positions (3 for each particle) are a complete set of commuting observables. Another classic example is the n,l,m,s basis for the states of the hydrogen atom.

For free boson fields, this concept seems to carry over well into QFT. For instance, in the case of a complex scalar field, the real and imaginary parts of the field at each point (on a spacelike hypersurface) are Hermitian and commute, so we can think of the well-defined field configurations as "basis states", and then a general state will be a functional giving a quantum amplitude to each configuration.

This "simple" setup obviously does not work for fermion fields. There, we are given anticommutation relations, which don't seem very helpful for defining basis states. Even the real and imaginary parts of the field at the same point do not commute.

What would a complete set of commuting observables look like for a fermion field, say a free Dirac field, expressed in terms of the field operators?
 
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maline said:
What would a complete set of commuting observables look like for a fermion field, say a free Dirac field, expressed in terms of the field operators?
quadratic expressions in the fermion fields
 
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A. Neumaier said:
quadratic expressions in the fermion fields
Yes, I guessed that that could be a good direction. Do you have a detailed idea for a complete set? Can the products be arranged so as to form, say, eight commuting Hermitian operators (for the real & imaginary parts of the four components) at each space point? What would be the spectra of these operators?
 
  • #4
maline said:
Yes, I guessed that that could be a good direction. Do you have a detailed idea for a complete set? Can the products be arranged so as to form, say, eight commuting Hermitian operators (for the real & imaginary parts of the four components) at each space point? What would be the spectra of these operators?
Strictly speaking, this is an ill-defined problem as the fields are distribution-valued only and hence have no spectra.

But if you discretize space you get a finite collection of qubits, and you can diagonalize each one separately. Then take a continuum limit.
 
  • #5
Okay, so we're talking about operators with eigenvalues zero and one? A yes/no answer to "is there a particle at this point"?
Would there be four or eight such?
 

1. What are commuting observables for Fermion fields?

Commuting observables for Fermion fields are quantities that can be measured simultaneously without affecting each other. In other words, these observables can be measured at the same time without any interference or disturbance.

2. How do commuting observables for Fermion fields differ from commuting observables for Boson fields?

Commuting observables for Fermion fields differ from those for Boson fields because Fermions obey the Pauli exclusion principle, which states that no two identical Fermions can occupy the same quantum state. This leads to different mathematical calculations and different sets of commuting observables.

3. What is the significance of commuting observables in quantum mechanics?

In quantum mechanics, commuting observables play a crucial role in understanding and predicting the behavior of particles. By measuring these observables, we can determine the state of a particle and make predictions about its behavior in the future.

4. Can commuting observables change over time?

Yes, commuting observables can change over time. In quantum mechanics, the state of a particle can change with time, which can also affect the values of commuting observables. However, commuting observables remain constant during the time evolution of a particle.

5. How can commuting observables for Fermion fields be used in practical applications?

Commuting observables for Fermion fields have many practical applications, especially in quantum computing and quantum information processing. These observables can be used to encode and manipulate information in qubits, which are the building blocks of quantum computers.

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