Compactness/convergence in Banach spaces

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Discussion Overview

The discussion revolves around the concepts of compactness and sequential compactness in Banach spaces, particularly focusing on whether every bounded sequence in these spaces has a convergent subsequence. The scope includes theoretical aspects and specific examples related to finite-dimensional Banach spaces and \( \ell^p \) spaces.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant questions whether the statement "every bounded sequence has a convergent subsequence" holds in arbitrary finite-dimensional Banach spaces and in \( \ell^p \) spaces for \( 1 \leq p \leq \infty.
  • Another participant argues that the statement does not hold in \( \ell^2 \) by providing a counterexample with the sequence of standard basis vectors.
  • A participant inquires if the statement also does not hold for finite-dimensional Banach spaces.
  • In response, another participant asserts that it does hold for finite-dimensional spaces, citing their isomorphism to \( \mathbb{R}^n \).
  • A later reply mentions that in general, in metrizable spaces, compactness and sequential compactness are equivalent, noting that the unit ball is compact/sequentially compact in a normed vector space if and only if the space is finite-dimensional.

Areas of Agreement / Disagreement

Participants express disagreement regarding the validity of the statement in finite-dimensional Banach spaces and \( \ell^p \) spaces, with competing views presented without a clear consensus.

Contextual Notes

Some limitations include the dependence on definitions of compactness and sequential compactness, as well as the specific properties of the spaces being discussed, which remain unresolved.

TaPaKaH
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Been doing exercises on compactness/sequential compactness of objects in Banach spaces and some of my solutions come down to whether
"every bounded sequence has a convergent subsequence"
holds in

a) arbitrary finite-dimensional Banach space
b) lp, 1 <= p <= infinity

Does it?
 
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No, this does not hold. Consider the sequence in \ell^2:

x_1=(1,0,0,0,...)
x_2=(0,1,0,0,...)
x_3=(0,0,1,0,...)
and so on.
 
Doesn't hold for finite-dimensional Banach space as well?
 
TaPaKaH said:
Doesn't hold for finite-dimensional Banach space as well?

It does hold for finite dimensional spaces since those are isomorphic to \mathbb{R}^n.
 
Last edited:
Thank you!
 
In general, in metrizable spaces, compactness and sequential compactness are

equivalent. The unit ball is compact/seq. compact in a normed v.space V iff

V is finite-dimensional.
 

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