Comparing Electron Mass in Different Speeds

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Homework Help Overview

The discussion revolves around the mass of an electron at different speeds, specifically comparing its rest mass in a computer monitor versus its mass in a particle accelerator. The original poster presents calculations using relativistic mass equations to determine how much heavier the electron is in the accelerator.

Discussion Character

  • Mathematical reasoning, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relativistic mass equation and its application to the problem. There are attempts to calculate the mass of the electron at two different speeds, with some participants questioning the correctness of the calculations and the interpretation of the results.

Discussion Status

There is an ongoing examination of the calculations presented, with some participants noting discrepancies in the values obtained. Guidance is offered regarding potential errors in the calculations, and there is recognition of the need to clarify whether the rest mass or relativistic mass is being calculated.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is also confusion regarding the definitions of mass being used in the context of relativistic physics.

wilson_chem90
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Homework Statement


An electron has a rest mass of 9.11 x 10^-31 kg. The speed of the electron in the cathode ray tube of your computer monitor is 4.00 x 10^7 m/s. However, the speed of the electron is 0.98 c in a particle accelerator used in cancer therapy. How many times heavier is the electron in the particle accelerator than in the computer monitor?


Homework Equations


m = mo/ sqrt(1 - v^2/c^2)


The Attempt at a Solution


mo1 = m sqrt(1 - v^2/c^2)
= (9.11 x 10^-31 kg) sqrt{ 1 - (4.00 x 10^7 m/s)^2/(3.00 x 10^8 m/s)^2}
= (9.11 x 10^-31 kg) sqrt(0.017777777)
= (9.11 x 10-31 kg)(0.13333333)
= 1.21 x 10^-31 kg

mo2 = (9.11 x 10-31 kg) sqrt{1 - (0.98 c)2/c^2}
= (9.11 x 10-31 kg)(0.198997)
= 1.81 x 10^-31 kg

(1.81 x 10^-31 kg)/(1.21 x 10^-31 kg)
= 1.496 times

Therefore the electron is approx. 1.5 times heavier in the particle accelerator than it is in the computer monitor.


Is this correct?
Thanks
 
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Your equations are correct but I am getting different values for mo1 and mo2 than you. For your value of mo1, you forgot to do 1 minus (4.00 x 10^7 m/s)^2/(3.00 x 10^8 m/s)^2. Instead you just took the second quantity and took the square root. For mo2, it looks correct, but when I calculate it I get a different answer. Maybe retype all the numbers into your calculator again and see if it was a typing error.
 
did you get (9.03 x 10^-31 kg) for m1? and (1.81 x 10^-31 kg) for m2?
 
but now it doesn't make sense, cause those answers are suggesting that the electron is heavier in the computer monitor than the particle accelerator
 
i just realized why this whole thing is completely wrong. i need to find m, not mo so the equation is completely wrong.

the equation is m = mo/ sqrt(1 - v^2/c^2)

so when i put all the numbers in for both sides

m1 = 9.19 x 10^-31 kg
m2 = 4.58 x 10^-31 kg

but still m2 should be heavier cause its in a particle accelerator, and the speed is much more significant..
 
Your m2 should be 4.58 x 10^-30 kg. Your off by an order of magnitude.
 
i see that now, sorry, thanks for helping me, honestly.
 

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