Comparing Momentum of Two Carts with Different Masses

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SUMMARY

The discussion centers on comparing the momentum of two carts with different masses, specifically a 0.2 kg plastic cart (Cart A) and a 20 kg lead cart (Cart B), both subjected to equal forces over a distance of 1 meter. It is established that while Cart A achieves a higher velocity due to its lower mass, the significantly greater mass of Cart B results in a higher momentum overall. The key takeaway is that momentum is calculated as the product of mass and velocity, and since the work done (force multiplied by distance) is the same for both carts, this leads to a definitive conclusion regarding their respective momenta.

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  • Basic knowledge of momentum calculation (mass x velocity)
  • Familiarity with the concept of work done (force x distance)
  • Basic kinematics principles
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einsteinette
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Hello there, I am having difficulty with this question:

A 0.2 kg plastic cart (Cart a) and a 20 kg (Cart b) lead cart can both roll without friction on a horizontal surface. Equal forces are used to push the two carts forward for a distance of 1 m, starting from rest. Which cart has the greater momentum, after the full 1m?

So I was thinking that since you apply equal forces to push the two carts, Cart A would have a higher velocity. But when you do the momentum of the two carts together, the larger mass of cart B would make up for the difference of velocity. If I'm right about the velocity thing that is.

mava = 0.2Va(>vb)
mbvb = 20Vb(<va)

So the momentum would be somewhat equal?
 
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einsteinette said:
So I was thinking that since you apply equal forces to push the two carts, Cart A would have a higher velocity.
That's true, but you need to figure out how much higher is the velocity of Cart A. Hint: Since equal force is exerted for equal distance, what can you say is the same for the two carts after the push?
 
The force applied and the rate of deceleration?
 
einsteinette said:
The force applied and the rate of deceleration?
The force is the same but the accelerations are not. But you can use Newton's 2nd law and some kinematics to figure out the velocity of each cart after it is pushed. Then you can compare momentum.

But another way is to recognize what force*distance gives you, and use that to figure out the velocity and momentum.
 
Ahh so you mean work done is the same. I think I get it now. Thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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