Comparing Momentum of Two Carts with Different Masses

Click For Summary

Homework Help Overview

The discussion revolves around comparing the momentum of two carts with significantly different masses after being pushed by equal forces over the same distance. The subject area includes concepts from mechanics, specifically momentum, force, and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between force, mass, and momentum, questioning how the different masses affect the final velocities and thus the momenta of the carts. There is discussion about the implications of applying equal forces and how that relates to acceleration and velocity.

Discussion Status

Participants are actively engaging with the problem, with some suggesting that the work done on both carts is the same, which may lead to insights about their velocities and momenta. There is an ongoing exploration of how to apply Newton's laws and kinematic equations to analyze the situation further.

Contextual Notes

There is a focus on understanding the implications of equal force applied to carts of different masses, and participants are considering the assumptions related to frictionless motion and the initial conditions of the carts.

einsteinette
Messages
12
Reaction score
0
Hello there, I am having difficulty with this question:

A 0.2 kg plastic cart (Cart a) and a 20 kg (Cart b) lead cart can both roll without friction on a horizontal surface. Equal forces are used to push the two carts forward for a distance of 1 m, starting from rest. Which cart has the greater momentum, after the full 1m?

So I was thinking that since you apply equal forces to push the two carts, Cart A would have a higher velocity. But when you do the momentum of the two carts together, the larger mass of cart B would make up for the difference of velocity. If I'm right about the velocity thing that is.

mava = 0.2Va(>vb)
mbvb = 20Vb(<va)

So the momentum would be somewhat equal?
 
Physics news on Phys.org
einsteinette said:
So I was thinking that since you apply equal forces to push the two carts, Cart A would have a higher velocity.
That's true, but you need to figure out how much higher is the velocity of Cart A. Hint: Since equal force is exerted for equal distance, what can you say is the same for the two carts after the push?
 
The force applied and the rate of deceleration?
 
einsteinette said:
The force applied and the rate of deceleration?
The force is the same but the accelerations are not. But you can use Newton's 2nd law and some kinematics to figure out the velocity of each cart after it is pushed. Then you can compare momentum.

But another way is to recognize what force*distance gives you, and use that to figure out the velocity and momentum.
 
Ahh so you mean work done is the same. I think I get it now. Thanks!
 

Similar threads

  • · Replies 32 ·
2
Replies
32
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
Replies
18
Views
3K
  • · Replies 40 ·
2
Replies
40
Views
5K
Replies
7
Views
3K
  • · Replies 24 ·
Replies
24
Views
4K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 3 ·
Replies
3
Views
5K