Comparing Two Balls' Heights: A Physics Problem

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The discussion centers on a physics problem involving two balls: a blue ball thrown upward with an initial speed of 23.5 m/s from a height of 0.9 meters, and a red ball thrown downward with an initial speed of 11.9 m/s from a height of 31.4 meters, 2.9 seconds later. The gravitational acceleration affecting both balls is 9.81 m/s². The key equations for the heights of the balls over time are derived, allowing for the calculation of the red ball's height 3.77 seconds after the blue ball is thrown and determining when both balls are at the same height.

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A blue ball is thrown upward with an initial speed of 23.5 m/s, from a height of 0.9 meters above the ground. 2.9 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 11.9 m/s from a height of 31.4 meters above the ground. The force of gravity due to the Earth results in the balls each having a constant downward acceleration of 9.81 m/s^2.

The Two questions are the following:

What is the height of the red ball 3.77 seconds after the blue ball is thrown?

and

How long after the blue ball is thrown are the two balls in the air at the same height?

Thanks for help much appreciated.
 
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Can you set up the equation to describe the blue ball?

Then set up a similar equation for the red ball but you will have to shift the time coordinate for the red ball by 2.9 seconds. From there it should be easy.
 


Got it thanks :)
 

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