A blue ball is thrown upward with an initial speed of 20.4 m/s, from a height of 0.5 meters above the ground. 2.5 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 9.8 m/s from a height of 23.9 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.
How long after the blue ball is thrown are the two balls in the air at the same height
The Attempt at a Solution
The height is different because i chose the blue ball as reference point.
I plugged the values into the equation and equated them giving me:
further simplifying i get....
which is wrong. can someone tell me where i went wrong?