Completely Inelastic Collision

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Discussion Overview

The discussion revolves around the concept of completely inelastic collisions, focusing on the mathematical proof of energy loss when two objects collide and stick together. Participants explore the relationship between kinetic energy and momentum in these scenarios, examining different frames of reference and the implications of conservation laws.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant is attempting to mathematically prove that maximum energy loss occurs in completely inelastic collisions, starting with a case where one object is stationary.
  • There is a suggestion to analyze the problem in a frame where total momentum is zero, which may simplify the understanding of pre- and post-collision states.
  • Another participant questions the differentiation of kinetic energy and its relationship to momentum, suggesting that the equations presented may not hold true in the context of inelastic collisions.
  • It is noted that while momentum is conserved in both elastic and inelastic collisions, kinetic energy is not conserved in inelastic collisions, leading to energy loss to other forms.
  • A later reply proposes using the center of mass reference frame, where the objects are at rest post-collision, indicating that this frame reflects a minimum energy state.

Areas of Agreement / Disagreement

Participants express differing views on the conservation of momentum and kinetic energy in inelastic collisions. While there is agreement that momentum is conserved, there is contention regarding the implications for kinetic energy and the validity of certain equations presented.

Contextual Notes

Participants highlight the need for careful consideration of frames of reference and the definitions of kinetic energy and momentum. There are unresolved mathematical steps and assumptions regarding the conditions of the collision that affect the discussion.

MathewsMD
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I'm currently trying to make a proof to convince myself that when two object collide and stick afterwards, there is maximum energy loss. I've been thinking about it and trying to come up with a mathematical proof to solidify the idea in my head.
Please tell me if there's any errors in my explanation or if there's anything that should be added.

Case 1: object 1 is moving and object 2 is stationary (with no external forces, a frame of reference can always be used in which the motion is 0 m/s, and I realize this is a proof in itself, but I want to come up with something mathematically instead of intuitively)

Ki = (1/2)m1vi2 [1]

Taking the derivative and solving for 0 will give me an extreme value for the kinetic energy.

Kf = (1/2)(m1+m2)vf2 [2]

K'f=p=(m1+m2)vf
and if vf=0 m/s, then this system will have 0 J (which, using the right frame of reference, is possible in any situation where the velocity of the two "stuck" objects is constant"

pi = pf since there is no net external force
m1vi=(m1+m2)vf
vf=m1vi/(m1+m2) [3]

Plugging [3] into [2] and dividing by [1], to see the ratio between Kf and Ki

=[(1/2)(m1)[m12vi2/(m1+m2)2]/(1/2)m1vi2

=m12/(m1+m2)2

I'm just confused now since this ratio doesn't seem to tell me much about two kinetic energies, does it? What else should I do now?
 
Last edited:
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MathewsMD said:
I'm just confused now since this ratio doesn't seem to tell me much about two kinetic energies, does it? What else should I do now?

Try working the problem in a frame in which the total momentum is zero. Then, before you go through the work of finding the extreme value, look carefully at the pre-collision and post-collision state.
 
Firstly, where K is kinetic energy, m is mass, v is velocity, and p is momentum, it could be technically debated that, if:
Kf = (1/2)(m1+m2)vf2 [2]
then:
K'f ≠ p = (m1+m2)vf
What has K been differentiated with respect to?

Another more easily addressed problem appears to be;
pi = pf
This is true if momentum is conserved, as is the case with ideal elastic collisions. In an inelastic collision, KE from equation [1] in the OP is lost to heat and other processes involved in the coalescing of the two objects, regardless of whether the final velocity; has been fixed to be zero, is measured to be zero, or otherwise. So pi ≠ pf , and therefore equation [3] is incorrect.

Lastly if K is dependent on v, and the final velocity of the coalesced objects is 0m.s-1, it becomes clear that the ratio Kf / Ki provides no useful information.
 
mic* said:
This is true if momentum is conserved, as is the case with ideal elastic collisions.

Momentum is always conserved, in both elastic and inelastic collisions, whether ideal or not.
 
Use the center of mass reference frame. In this frame the objects are at rest after the collision (by momentum conservation) which means the energy is a minimum (since its zero, and cannot be negative).
 

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