Complex derivative of x: ((x)^(1/x))'

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Homework Help Overview

The problem involves finding the derivative of the function ((x)^(1/x)). The subject area pertains to calculus, specifically the differentiation of functions involving exponentials and logarithms.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the potential usefulness of rewriting the function in terms of the exponential function and logarithms to facilitate differentiation. There is mention of applying the chain rule in the differentiation process.

Discussion Status

Some participants have offered insights into rewriting the function for easier differentiation and have highlighted the importance of understanding the underlying relationships in the expressions. There is an ongoing exploration of different approaches to the problem.

Contextual Notes

The original poster expresses a desire for a complete process to enhance understanding, indicating a need for guidance rather than direct answers. There is a reminder about the importance of engaging with the material for learning purposes.

Ondina
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<<Moderator note: Remember that filling in the complete homework template is mandatory in the homework forums. This thread has not been deleted due to containing relevant replies.>>

1. Homework Statement

((x)^(1/x))'

Homework Equations


This probably isn't overly dificult, but it has got me stumped, if anyone would be so kind as to reply, would you please post the entire process, so that I can try to better understand it. Thank you very much

The Attempt at a Solution

 
Last edited by a moderator:
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Hello Ondina, welcome to PF :smile: !

<<Moderator note: Removed comment on now deleted full solution.>>

That way you are robbed from a learning experience that might have helped you in a future exercise.

If you see something like ##x^{1\over x}## it's sometimes helpful to write it as ##e^{\ln x\over x}##. To take the derivative you use the chain rule: $$\left (e^{\ln x\over x} \right )'= e^{\ln x\over x} \; \left ({\ln x\over x} \right )'
$$.
 
Last edited by a moderator:
BvU is making use of the relationship that:

##y = e^{\ln y}##

This follows from the definition of the natural log of a quantity: lny is the power you have to raise e to in order to get y.

Chet
 
Thank you all very much for your help!
 

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