Complex Integration with a removable singularity

  • #1
Hi,

I'm trying to make headway on the following ghastly integral:

[tex] \int_0^{\infty} x^{\frac{3}{2}}e^{-xd} J_o(rx) \frac{\sin (\gamma \sqrt{x}\sqrt{x^2+\alpha^2}t)}{\sqrt{x^2+\alpha^2}}\ dx [/tex]


where [itex] d,r, \alpha, \gamma ,t \in \mathbb{R}^+[/itex] and [itex]J_o[/itex] is the zeroth order Bessel function of the first kind. Normally I wouldn't think I'd have a shot at finding this in closed form, but because there is a (removable) singularity, maybe there's a chance to exploit some complex analysis.

My attempts so far have all focused on making a branch cut along the positive real axis and integrating around a modified keyhole, which goes along the real axis, then follows an arc to the imaginary axis, going around the singularities, before arcing back to the real axis. This has not led to anything productive. It reminds of the contour used in a Bromwich integral.

Any suggestions? They'd be greatly appreciated.

Cheers,

Nick
 

Answers and Replies

  • #2
In principal, I would say it's a good idea to exploit contour integration, but keep in mind that when you have a removable singularity, the residue is 0, so the straight-forward way where you just consider the residue and argue that the arc doesn't contribute won't work.
 

Related Threads on Complex Integration with a removable singularity

Replies
7
Views
4K
  • Last Post
Replies
4
Views
1K
Replies
1
Views
985
Replies
21
Views
751
Replies
6
Views
1K
  • Last Post
Replies
1
Views
9K
Replies
2
Views
6K
Top