Complex Logarithm: Solving tan-1[(2sqrt(3) - 3i)/7]

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SUMMARY

The discussion focuses on solving the complex logarithm for the expression tan-1[(2sqrt(3) - 3i)/7] using the formula tan-1z = (1/2i)ln[(1+iz)/(1-iz)]. The initial transformation leads to the expression (1/2i)ln[(i2sqrt(3) + 10)/(i2sqrt(3) + 4)]. Participants emphasize the importance of expressing the logarithm's argument in the form a+bi to facilitate the extraction of magnitude and angle. Key insights include the necessity of verifying signs and utilizing complex conjugates for simplification.

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Homework Statement



If

tan-1z = (1/2i)ln[(1+iz)/(1-iz)]

then find

tan-1[(2sqrt(3) - 3i)/7]



The Attempt at a Solution



I haven't gotten very far, but this is what I have so far:

tan-1[(2sqrt(3) - 3i)/7]

= (1/2i)ln[(i2sqrt(3) + 10)/(i2sqrt(3) + 4)]

Where do you go from there? I'm not completely familiar with the rules of complex logarithms. Can you split it into real and imaginary parts?
 
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You should check what you already have. I think you've already got a sign wrong. But you want write the expression inside the log in the form a+bi with a and b real, so you can find it's magnitude and angle. You know how to do that with a ratio using complex conjugates, right?
 

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