(Complex number) I have no idea on this

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(Complex number) I have no idea on this :(

Homework Statement


If z lies on circle |z|=2, then show that
[tex]\left\lvert \frac{1}{z^4-4z^2+3} \right\rvert ≤ \frac{1}{3}[/tex]


Homework Equations





The Attempt at a Solution



Please somebody give me an idea. [URL]http://209.85.48.12/11451/115/emo/dizz.gif[/URL]
 
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Answers and Replies

  • #2
Fredrik
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Consider any fraction x/y where x,y>0. If you replace y with something smaller, you make the fraction larger. In other words, if y>u, then x/y<x/u. Can you find something that's smaller than [itex]|z^4-4z^2+3|[/itex]?

I haven't verified that that this gives us something useful, but it seems like the obvious place to start.
 
  • #3
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Can you find something that's smaller than [itex]|z^4-4z^2+3|[/itex]?
No. How will i do that? :confused:
 
  • #4
verty
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Sorry, I didn't notice this was for complex numbers.

If |z| <= 2, |z|^2 = |z^2| <= 4, ...
 
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  • #5
Fredrik
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No. How will i do that? :confused:
The triangle inequality. [tex]|z|-|w|\leq|z+w|\leq|z|+|w|[/tex]
 
  • #6
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The triangle inequality. [tex]|z|-|w|\leq|z+w|\leq|z|+|w|[/tex]
Okay, but how i will apply it here? :confused:

Should it be like this:-
[tex]|z^4-4z^2+3|≤ |z^4|+|3-4z^2|[/tex]
 
  • #7
Fredrik
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Okay, but how i will apply it here? :confused:

Should it be like this:-
[tex]|z^4-4z^2+3|≤ |z^4|+|3-4z^2|[/tex]
That inequality is correct, but you need to find something smaller than (or equal to) [itex]|z^4-4z^2+3|[/itex]. I don't think I can tell you much more without solving the whole problem for you. I'll just add that I have verified that this approach gives us the correct answer.
 
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  • #8
Fredrik
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I think it's easier to just use the triangle inequality twice.
 
  • #9
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That inequality is correct, but you need to find something smaller than (or equal to) [itex]|z^4-4z^2+3|[/itex]. I don't think I can tell you much more without solving the whole problem for you. I'll just add that I had verified that this approach gives us the correct answer.
Are you asking me this:-
[tex]|z^4-4z^2+3|≥ |z^4|-|3-4z^2|[/tex]
 
  • #10
Fredrik
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Are you asking me this:-
[tex]|z^4-4z^2+3|≥ |z^4|-|3-4z^2|[/tex]
Yes. Now do something similar to the second term on the right, to get something even smaller than (or equal to) [itex]|z^4|-|3-4z^2|[/itex].
 
  • #11
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Yes. Now do something similar to the second term on the right, to get something even smaller than (or equal to) [itex]|z^4|-|3-4z^2|[/itex].
How will i do that? How will i apply the triangle inequality? :confused:
 
  • #12
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Note that z4-4z2+3=(z2-1)(z2-3), and use de Moivre's formula.


ehild
I tried that but i am not able to understand how would i apply De Moivre's theorem?
 
  • #13
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What is te magnitude of z2?

ehild
Magnitude of z2? Now you are making me confused (which i am already). :confused:
 
  • #14
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Magnitude is the same as absolute value. What is it for z?

ehild
For z its |z| or [itex]\sqrt{x^2+y^2}[/itex]
and for z2, it is [itex]x^2+y^2[/itex]

Right..?
 
  • #15
I like Serena
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Hi Pranav-Arora! :smile:

Can you also write z as an exponential power?

And does your problem statement say anything about |z|?

So what can you say about |z2|?
 
  • #16
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Hi Pranav-Arora! :smile:

Can you also write z as an exponential power?

And does your problem statement say anything about |z|?

So what can you say about |z2|?
Hi ILS! :)

|z|=2
therefore |z2|=4. :)
 
  • #17
I like Serena
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Yep! [URL]http://i154.photobucket.com/albums/s271/R2Garnets/Smileys/Smiley-Duh.gif[/URL]

So what can you say about |z2-1|?
 
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  • #18
Fredrik
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How will i do that? How will i apply the triangle inequality? :confused:
If I tell you that, I will have completely solved the problem for you. Isn't the 99% I've already done enough? You have to try something yourself.

Have you tried anything at all? I only gave you two inequalities, so if the first one you tried didn't work, it has to be the other one. It looks like you're not even trying, and just want someone else to do 100% of the work for you.
 
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  • #19
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Yep! [URL]http://i154.photobucket.com/albums/s271/R2Garnets/Smileys/Smiley-Duh.gif[/URL]

So what can you say about |z2-1|?
Should it be equal to 3? :confused:

If I tell you that, I will have completely solved the problem for you. Isn't the 99% I've already done enough? You have to try something yourself.

Have you tried anything at all? I only gave you two inequalities, so if the first one you tried didn't work, it has to be the other one. It looks like you're not even trying, and just want someone else to do 100% of the work for you.
No Fredrik, i am trying myself too. But i am really not able to work out what should i do next?
Complex number is the weakest point of mine in mathematics and it is really really hard for me. I try to do my best but if you think that you have told me the 99% of the solution, i will try it again. :)
 
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  • #21
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No. How did you get to 3?
I thought |z2|=4.
or |z2|-1=3

Since |z2|-1=|z2-1|
therefore |z2-1|=3

EDIT: I have realised that |z2|-1=|z2-1| does not hold true at 0.

What should i do now? :(
 
  • #23
I like Serena
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Consider that z is not a real number, but a complex number.
It is represented by a 2D vector.
The absolute value is not the regular absolute value of real numbers, but the length of the vector that z represents.
 
  • #25
Fredrik
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No Fredrik, i am trying myself too.
You haven't shown any of your work. When it seems to you that a method that we have suggested may not work, you have to post your reasons for thinking so.

But i am really not able to work out what should i do next?
I don't know how that's possible, since I gave only gave you two equalities and pointed out the specific term you should use one of them on. There are only two things you can even try. What do you get when you try those two things?
 

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