Complex number multiple choice

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Homework Help Overview

The discussion revolves around the properties of complex numbers, specifically examining the equation Z = 1/(z conjugate) and its implications for the nature of Z. Participants explore the conditions under which Z can be real, considering the geometric interpretation of the equation in the complex plane.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants attempt to express Z in terms of its real and imaginary components, questioning whether the resulting expression indicates that Z is purely real. They also explore the geometric meaning of the equation a² + b² = 1 and its implications for the values of a and b.

Discussion Status

The discussion is active, with participants offering various interpretations of the conditions for Z to be real. Some suggest that b must be zero for Z to be purely real, while others question the validity of the original problem and explore the geometric significance of the expressions involved.

Contextual Notes

There is some uncertainty regarding the phrasing of the original question and whether it accurately reflects the mathematical relationships being discussed. Participants are also considering the implications of the unit circle in the context of complex numbers.

alijan kk
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Homework Statement


If Z= (1)/(z conjugate) then Z : ?

Homework Equations

The Attempt at a Solution


let z= a+bi
the z conjugate= a-bi

(a+bi)=(1)/(a-bi)

(a+bi)(a-bi)=1

a2+b2=1

does it tell from this expresssion that the complex number is a pure real ?
 
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alijan kk said:
does it tell from this expresssion that the complex number is a pure real ?
What is the condition on ##a## and ##b## for ##Z## to be real?
 
No. What does a2 + b2 = 1 mean geometrically? Think of a graph in the complex plane.
 
DrClaude said:
What is the condition on ##a## and ##b## for ##Z## to be real?
b should be zero if the complex number is pure rule
can we put b= 0
 
alijan kk said:
b should be zero if the complex number is pure rule
can we put b= 0
We can set b = 0, but we don't have to, so this is not the answer to the problem.
 
DrClaude said:
We can set b = 0, but we don't have to, so this is not the answer to the problem.
so this a wrong question in my book ?
 
alijan kk said:
so this a wrong question in my book ?
No, the question asks about what you can say about a number for which ##z = \bar{z}^{-1}##. See @mjc123's post above for a hint.
 
mjc123 said:
No. What does a2 + b2 = 1 mean geometrically? Think of a graph in the complex plane.
a unit circle ,
 
the inverse is 1/a2+b2 of a2+y2 and that is a real number ! am i right ?
 
  • #10
##a^2+b^2## will always be real. That doesn't tell you anything about ##z##.
 
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  • #11
DrClaude said:
##a^2+b^2## will always be real. That doesn't tell you anything about ##z##.

options are:
z is purely imaginary
z is any complex number
z is real
none of these
 
  • #12
alijan kk said:
options are:
z is purely imaginary
z is any complex number
z is real
none of these

if it doesn't tell about z ,, then should the answer be (none of these)
 
  • #13
It does tell you something about z, but not one of those options. You got it in post #8 - a unit circle. More specifically, z is any complex number represented by a point in the complex plane that lies on the circumference of a unit circle centered on the origin.
Are you familiar with the polar notation for complex numbers: z = re, where r2 = a2+b2 and tanθ = b/a?
Then z* = re-iθ and 1/z* = (1/r)e
So z = 1/z* for any number for which r = 1, for any value of θ.
 
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