Complex-Phasor (Moved from physics)

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Homework Help Overview

The discussion revolves around the analysis of two alternating currents that are out of phase, specifically one at 4 volts and the other at 3 volts with a phase difference of 27°. Participants are tasked with drawing phasors, combining them, and labeling the peak voltage.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss their attempts to draw phasors and calculate the combined phasor's voltage. Questions arise regarding the correctness of their drawings and calculations, as well as how to properly label the results.

Discussion Status

Some participants have shared their images and calculations, seeking validation of their work. Others have provided feedback on the need for clearer representations of the phasors and the combined phasor, indicating a productive exchange of ideas without reaching a consensus.

Contextual Notes

There is mention of confusion regarding the requirements for the combined phasor and how to represent it accurately in the context of the homework assignment.

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Homework Statement



Two alternating currents are applied out of phase with each other. One is 4 volts and the other is 3 volts 27° out of phase.

These can be written as (4, 0°) and (3, 27°)


Homework Equations



a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value



The Attempt at a Solution



a)A rough drawing on paint http://imageshack.us/photo/my-images/3/plotb.jpg/

b) I know A= 6.8106 volts by using this formula

r=√a2+b2

r=3cos27 + 4i + i(3sin 27)

r=√(3cos27 + 9)2 + (3sin27)2

=6.81v

angle=0.2014


Image 2 attached.


Please look at both images, which are correct
 

Attachments

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maali5 said:

Homework Statement



Two alternating currents are applied out of phase with each other. One is 4 volts and the other is 3 volts 27° out of phase.

These can be written as (4, 0°) and (3, 27°)

Homework Equations



a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value

The Attempt at a Solution



a)A rough drawing on paint http://imageshack.us/photo/my-images/3/plotb.jpg/

b) I know A= 6.8106 volts by using this formula

r=√a2+b2

r=3cos27 + 4i + i(3sin 27)

r=√(3cos27 + 9)2 + (3sin27)2

=6.81v

angle=0.2014Image 2 attached.Please look at both images, which are correct

Is there a question here?
 
LCKurtz said:
Is there a question here?

Yeh

(4,0°) and (3,27°)

a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value
 
LCKurtz said:
Is there a question here?

maali5 said:
Yeh

(4,0°) and (3,27°)

a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value

Well, yes, those are the questions you are working on. I knew that. And I see you have worked on them. What is your question that you are seeking help on here?
 
I have drawn two images. Also done a calculation.

I was wondering if the images and calculation are correct?
 
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number.
 
LCKurtz said:
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number.

b)How should I draw a phasor?

c) Again any help on what number ?
 
try sketching both graphs on the same axis... then imagine what the sum might look like.
 
maali5 said:
b)How should I draw a phasor?
The same way you drew phasors for part (a).
c) Again any help on what number ?

You already calculated it, didn't you?
 
  • #10
LCKurtz You have confused me.

Let's rewind back- I have drawn two images

i) (http://imageshack.us/photo/my-images/3/plotb.jpg

ii) The attached image



Then you said

"
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number."



My reply to you question:

For the phasor image would that not be image (i) and for c the number (=6.81v ).

And last but not least should I label (6.81v) on graph B.


Thanks again
 
  • #11
maali5 said:
LCKurtz You have confused me.

Let's rewind back- I have drawn two images

i) (http://imageshack.us/photo/my-images/3/plotb.jpg

ii) The attached image



Then you said

"
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number."



My reply to you question:

For the phasor image would that not be image (i)

Part (a) Said draw both phasors. That's apparently what you did in image 1, although I would put a little arrowhead on the tips of both.

and for c the number (=6.81v ).

And last but not least should I label (6.81v) on graph B.

Thanks again

Part (b) asks for the "combined phasor". That is another phasor like in part (a). It is just the result of adding the two given phasors and would be easy to include in your image 1. But when it asks for the combined phasor "between 0 and 360" maybe it means the corresponding sine wave like in your other image. Either way the 6.81 is the amplitude of the sine wave you have drawn and is also the length of the combined phasor, which you have not drawn yet.
 
  • #12
Thank you!

One last question for the combined phasor. How should I be able to draw that?

Would you please be able to attach simple exam on how to draw one? As I do not where to start.
 
  • #13
maali5 said:
Thank you!

One last question for the combined phasor. How should I be able to draw that?

Would you please be able to attach simple exam on how to draw one? As I do not where to start.

You calculated its length and angle (in radians) in your first post. Just draw it like you did the others. Or you could geometrically use the parallelogram rule for adding the two vectors (phasors) in your first picture. Or if it's the sine wave they want, you have already drawn it.
 

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