1. Jun 6, 2010

### asdfphysics

1. The problem statement, all variables and given/known data

http://i45.tinypic.com/314te39.jpg

I am suppose to create a RIVP chart with that circuit shown above.

R1 = 10 ohms
R2 = 14 ohms
R3 = 9 ohms
R4 = 11 ohms
R5 = 5 ohms
R6 = 9 ohms
The voltage of the battery is 8V.

2. Relevant equations
The current is not given so I am assuming that I need to solve everything with Kirchhoff's rules but I'm not sure how to do that. I also noticed that the current can go in many directions.

3. The attempt at a solution

I know that the equations I have to use are P=IV and V=IR
I attempted to construct my RIVP chart and there were a lot of components that I need to solve for. I am not sure how to start the problem since the current is not given.

2. Jun 7, 2010

### Stonebridge

You don't need to use Kirchhoff for this problem. It's possible, stepwise, to reduce all these resistors to one; and then find the main current in the cell.
Start by replacing R4 and R6 with, say R7.
R4 and R6 are in parallel.
Then this R7 is in series with R5. Replace R7 and R5 with, say, R8.
Work your way through the other resistors until there is just one left.

3. Jun 8, 2010