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Introductory Physics Homework Help
Component resolution of g on an inclined plane
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[QUOTE="themselv, post: 4499448, member: 487595"] [ATTACH=full]163865[/ATTACH] I realize that an expression for g should be g = a/sin(theta) by looking at the angle that's formed perpendicular to the plane. However, if I just look at angle theta in the bottom left corner, why am I not justified in saying g = sin(theta)*a, since to me it appears that the sine of angle theta is just opposite over hypotenuse, or g/a. [/QUOTE]
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Introductory Physics Homework Help
Component resolution of g on an inclined plane
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