Components of a covariant vector

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The discussion revolves around the calculation of components of a covariant vector \tilde{u} in two different basis sets in R^3. The user expresses confusion about how to compute \tilde{u}(\vec{e}_j) and the significance of the basis vectors in the calculations. They mention an interaction with their professor, who clarified some steps, specifically that \tilde{u}(\vec{e}_1) equals zero. The user seeks a simplified explanation of the concepts involved and recommendations for accessible reading materials on the topic. Overall, the thread highlights the challenges of understanding covariant vectors and the need for clearer educational resources.
roldy
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Homework Statement


Consider the following two basis sets (or triads) in {R}^3:

<br /> \{\vec{e}_1, \vec{e}_2, \vec{e}_3\} := \{(1, 0, 0), (0,1, 0), (0, 0, 1)\}<br />

<br /> \{\widehat{\vec{e}_1}, \widehat{\vec{e}_2}, \widehat{\vec{e}_3}\} := \{(1, 0, 0), (1,1, 0), (1, 1, 1)\}.<br />

Let a covariant vector \tilde{u} be defined by \tilde{u}(\alpha^i{\vec{e}_i} ):= \alpha^3-\alpha^2. Obtain explicitly the components of \tilde{u} relative to the corresponding bases \{\vec{e}_1, \vec{e}_2, \vec{e}_3\} and \{\widehat{\vec{e}_1}, \widehat{\vec{e}_2}, \widehat{\vec{e}_3}\}.


Homework Equations


<br /> \tilde{a}(\vec{b})=\tilde{a}(\beta^j\vec{e}_j):=\alpha_j\beta^j<br />


The Attempt at a Solution


My attempt at a solution is just me running around in a bunch of directions. I really don't have a clear understanding of how to approach this.
 
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Start by computing \tilde{u}(\vec{e}_j) for j = 1,2,3. (These are the components of \tilde{u} relative to the basis \{\vec{e}_1, \vec{e}_2, \vec{e}_3\}, or more properly speaking, relative to the corresponding dual basis.)

Then expand the new basis vectors \widehat{\vec{e}_j} in terms of the \vec{e}_k, and use that to compute \tilde{u}(\widehat{\vec{e}_j}) for j = 1,2,3.
 
I'm actually confused at how to do the first part, calculating \tilde{u}(\vec{e}_j).
I know I need to use this relationship \tilde{u}(\alpha^i{\vec{e}_i} ):= \alpha^3-\alpha^2.

So expanding the relationship:

<br /> \tilde{u}(\alpha^1\vec{e}_1+\alpha^2\vec{e}_2+\alpha^3\vec{e}_3)=\alpha^3-\alpha^2<br />

What does the above actually mean?

I asked my professor about this problem and he helped a little. He actually worked through a portion of it. This is what came about.

<br /> \tilde{u}(\vec{e}_1)=\tilde(u)\left((1)\vec{e}_1+(0)\vec{e}_2+(0)\vec{e}_3\right)=0-0=0<br />

The thing I don't understand about this is why are there basis \vec{e}_1, \vec{e}_2, \vec{e}_3 in the parenthesis when you are trying to figure out \tilde{u}(\vec{e}_1).

I need a really simplified (dumbed down) explanation on this. I'm not used of working with anything so abstract.

Would you know of any books that are easy on the reader?
 
Does anyone else have insight on this problem?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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