Finding Resultant of Displacements Using Unit Vectors

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The discussion revolves around calculating the resultant of three displacements from a golfer's putts expressed in unit vector notation. The first displacement is straightforward at (0)i, (2.5)j, while the second and third displacements require conversion to unit vectors, with the second being 4.8 m South-East and the third 5.7 m South-West. The confusion arises regarding the angles for the South-East and South-West directions, but it is clarified that these angles are typically 45 degrees. Finally, to find the angle for a single putt to the hole, the resultant vector is needed, and the tangent function is suggested for determining the angle based on the resultant's components.
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Homework Statement



A golfer takes three putts to get the ball into the hole of a level putting green. The first putt displaces the ball 2.5 m North, the second 4.8 m South-East and the third 5.7 m South-West.

Express each of these three displacements in unit vector notation where i is a unit vector pointing due East and j is a unit vector pointing due North.

E.g the first displacement is: (0)i, (2.5)j

The Attempt at a Solution



The first one is obvious but the other two aren't. For example for the second part the question says it is 4.8 m South-East BUT it doesn't say how many degrees due South-East. Without the angle, it is impossible for me to find the rectangular components (i.e 4.8 sin(\theta), 4.8 cos(\theta)). Any suggestions?
 
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When they say south of east or south of west the angle is always 45 degrees with east-west line.
 
Oh thanks! I found the three displacements in unit vector notation:

0i, 2.5j
3.39i, -3.39j
-4.03i, -4.03j

The question then asks:

Determine the angle in degrees (measured with respect to anticlockwise rotation from an axis pointing due East of the hole) to get the ball into the hole in a single putt.

What do I need to do to answer this problem? I'm a little confused...
 
Find the resultant of these three vectors.
Then tanθ = y/x
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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