Composite Functions and Uniform Convergence: A Closer Look

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SUMMARY

The discussion centers on the conditions under which the equality f(lim_{n\rightarrow\infty} g_{n}(x)) = lim_{n\rightarrow \infty} f(g_{n}(x)) holds true, specifically when f is a continuous function. It is established that if f is defined as f(g(x)) = ∫^{b}_{a} g(x) dx, then the equality is valid if g_{n}(x) converges uniformly. This highlights the importance of uniform convergence in the interchange of limits and integrals in the context of complex-valued functions.

PREREQUISITES
  • Understanding of uniform convergence in mathematical analysis
  • Familiarity with complex-valued functions
  • Knowledge of integral calculus, specifically definite integrals
  • Basic concepts of continuity in functions
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  • Study the concept of uniform convergence in detail
  • Explore textbooks on real and complex analysis that cover continuity and convergence
  • Investigate the Dominated Convergence Theorem for further insights on limits and integrals
  • Learn about the implications of uniform convergence in functional analysis
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travis0868
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When is the following true?

f(lim_{n\rightarrow\infty}\ g_{n}(x)) =

lim_{n\rightarrow \infty}\ f(g_{n}(x))

Does anyone know of a textbook that discusses this?
 
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Assuming f and g_n are complex-valued, iff f is continuous.
 
But what if f is the following function:

f(g(x)) = \int^{b}_{a} g(x) dx

If that's the case,

f(lim_{n\rightarrow\infty} g_{n}(x)) = \int^{b}_{a} lim_{n\rightarrow\infty}g_{n}(x) dx

and

lim_{n\rightarrow\infty} f(g_{n}(x)) = lim_{n\rightarrow\infty} \int^{b}_{a} g_{n}(x) dx

These two are equal only when g_{n}(x) is uniformly convergent.
 

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