Composition of functions - find range

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Homework Help Overview

The discussion revolves around the composition of functions, specifically focusing on finding the range of the composition of two functions, f(x) = x + 1 and g(x) = x^2, over the interval [-1, 1]. Additionally, participants explore the equality of two functions defined on different domains and codomains.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the composition of functions and the correct interpretation of (fog)(x). There is uncertainty about how to calculate the range of the composition and whether to consider different forms of the functions. Questions arise regarding the equality of two functions and the implications of their domains and codomains.

Discussion Status

Some participants have provided clarifications on the composition of functions and the nature of the functions being compared. There is an ongoing exploration of the definitions and properties of the functions involved, with no explicit consensus reached on all points.

Contextual Notes

Participants express confusion about the terminology used in the questions, particularly regarding the distinction between functions and questions. There is also discussion about the inclusion of certain values within specified sets, which affects the definitions of the functions.

sara_87
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Good evening guys, i have two stupid questions that I'm stuck on and i would be grateful if anyone could help

Question 1:

f(x)= x+1 g(x)=x^2

the domain in each case is the interval [-1,1] and belongs to the set of real numbers then find the range of:

(fog)(x)

My Answer:

i found (fog) to be x^2 +1 then i put in -1,0 and 1 to get the range

or should i do (fog)*(x) which would make it x^3 + x

Question 2:

determine which of the following questions are equal:

f:{1} -> N (the set N) and g:R-> R (the set R) be functions given by

f(x)=x-1 and g(x)=0

My Answer

f(x) not equal g(x)

because 0 doesn't belong to the set N ?

(i feel so dum asking these questions!)
 
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sara_87 said:
Good evening guys, i have two stupid questions that I'm stuck on and i would be grateful if anyone could help

Question 1:

f(x)= x+1 g(x)=x^2

the domain in each case is the interval [-1,1] and belongs to the set of real numbers then find the range of:

(fog)(x)

My Answer:

i found (fog) to be x^2 +1 then i put in -1,0 and 1 to get the range
correct
or should i do (fog)*(x) which would make it x^3 + x

No, (fog)(x) means f(g(x)), so you do as you did above.. apply g to the x, then apply f to g(x)

Question 2:

determine which of the following questions are equal:

f:{1} -> N (the set N) and g:R-> R (the set R) be functions given by

f(x)=x-1 and g(x)=0

My Answer

f(x) not equal g(x)

because 0 doesn't belong to the set N ?
correct
(i feel so dum asking these questions!)

No need to feel dumb: the only way to learn is to ask questions!
 
thanx cristo!
 
sara_87 said:
determine which of the following questions are equal:

what do you mean by 'question'? And what do you mean by 'which of them are equal'? Sorry, but that sentence doesn't make any sense, and I can't guess at what you mean.

f:{1} -> N (the set N) and g:R-> R (the set R) be functions given by

f(x)=x-1 and g(x)=0

well, those are two obviously unequal *functions*, since they have different domains and ranges. (And it is moot whether or not 0 is or is not in N.)

My Answer

f(x) not equal g(x)

because 0 doesn't belong to the set N ?

If 0 is not in your set N, then f is not even a properly defined function.

Even 'which of the following functions are equal?' doesn't make sense.
 
Last edited:
the question refers to the different parts of it

i.e determine which of the following questions are equal:

a)f:{1} -> N (the set N) and g:R-> R (the set R) be functions given by

f(x)=x-1 and g(x)=0

b) (another one)

c) (another one)

i left the question in plural form to avoid confusion...looks like i did the opposite.

also i was asking if 0 belonged to the set N...but now i know that it does and that the function f and g are not equal because they have different domains and co domains thanks to you.

'(And it is moot whether or not 0 is or is not in N.)'

what does moot mean?
 
sara_87 said:
the question refers to the different parts of it

i.e determine which of the following questions are equal:

This still doesn't make any sense. Even if you're to acutally put three parts to the question in it will not make sense. There are no questions at all, and it would be strange to ever ask when questions are equal.
a)f:{1} -> N (the set N) and g:R-> R (the set R) be functions given by

f(x)=x-1 and g(x)=0

b) (another one)

c) (another one)

i left the question in plural form to avoid confusion...looks like i did the opposite.

But surely you just have to read the sentence you wrote to understand that I'm not making any comment on mathematics. It genuinely is not something that made sense, nor does it even now.

It would be strange if the question actually asked 'are *those* two functions equal', because they clearly are not equal functions. Hence my continued confusion. And your answer that 0 was not in N didnt' help me work out what it was that you were trying to answer. It is very important to actually write the question you were asked, not what you think you were asked so that people can help.

also i was asking if 0 belonged to the set N...but now i know that it does and that the function f and g are not equal because they have different domains and co domains thanks to you.

'(And it is moot whether or not 0 is or is not in N.)'

what does moot mean?

If you're ever not sure of the meaning of a word, and a dictionary is not to hand, then you can either google for the meaning (there are lots of free dictionaries on the web), or just google the word itself, then in the slightly blue bar going across the screen above the results the words you searched for are listed, with links to definitions of all the words. I realize it would be shorter to actually define it for you, but this is useful information. There is no reason to ever be in doubt abuot the meaning of a word.
 
Last edited:
determine which of the following 'questions' are equal
damn i meant functions! not questions!

now it makes sense doesn't it?

even though i wrote the qusetion wrong and you said that it 'doesn't make any sense' you still managed to answer it for me...cheers!
 
Had I known that was precisely what the question asked, then I would have been duty bound *not* to have answered as I did. I didn't believe that they would actually ask that question of *those* two functions.
 

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