Compressed Air Energy Storage System

Click For Summary
SUMMARY

The discussion centers on calculating the work consumed by a Compressed Air Energy Storage (CAES) system compressor. The system operates at an intake pressure of 102.2 kPa and compresses air to 85 bar adiabatically at a flow rate of 168 kg/s. Key thermodynamic properties include specific heat at constant pressure (Cp) of 1.005 kJ/kgK and specific heat at constant volume (Cv) of 0.718 kJ/kgK. To determine the work done by the compressor, the user should focus on calculating the change in enthalpy and the compressed air temperature.

PREREQUISITES
  • Understanding of thermodynamics, specifically the first law of thermodynamics.
  • Familiarity with adiabatic processes and their implications in gas compression.
  • Knowledge of specific heat capacities (Cp and Cv) and their applications in energy calculations.
  • Ability to perform calculations involving enthalpy changes in gases.
NEXT STEPS
  • Calculate the compressed air temperature using the adiabatic process equations.
  • Determine the change in enthalpy (h2 - h1) for the air being compressed.
  • Apply the first law of thermodynamics to find the work done by the compressor.
  • Explore software tools for thermodynamic calculations, such as EES (Engineering Equation Solver).
USEFUL FOR

This discussion is beneficial for mechanical engineers, energy system designers, and students studying thermodynamics, particularly those focused on energy storage technologies and compressor design.

Isotropic
Messages
1
Reaction score
0

Homework Statement


I have a CAES system that takes air at a pressure of 102.2kPa and temp of 24 degrees C. It is compressed to 85 bar adiabatically at a rate of 168 kg/s. I know that Cp = 1.005 kJ/kgK and Cv = 0.718 kJ/kgK. The question is - determine the amount of work consumed by the compressor in kWh.

2. Relevant equation
Unsure

The Attempt at a Solution


Totally lost with this question, attempted a solution using -w = (h2-h1) and then U = Q + w, but i don't think i have the required values for that. Any help at all is greatly appreciated.
 
Physics news on Phys.org
Isotropic said:
Any help
Not sure I can answer the question fully, but I know where I would start: find the compressed temperature.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
23
Views
5K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
4K
  • · Replies 10 ·
Replies
10
Views
7K