Compute Right Coset of (1 2) in S3 X Z2

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Homework Help Overview

The problem involves computing the right coset of the element ((1 2), [1]) in the group S3 X Z2. Participants are discussing the nature of the element and whether it constitutes a subgroup or if it is simply an element within the group structure.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants explore the definition of the right coset and question whether ((1 2), [1]) should be treated as a subgroup or merely an element. Others suggest listing elements of S3 X Z2 and applying the operation to find the right coset.

Discussion Status

The discussion is ongoing, with participants expressing confusion about the terminology and the requirements of the problem. Some have proposed methods for computing the coset while others emphasize the need for clarification on the subgroup aspect.

Contextual Notes

There are uncertainties regarding the interpretation of the term "coset" in relation to the given element and whether assumptions about the subgroup generated by ((1 2), [1]) are necessary for the computation.

FanofAFan
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Compute the right coset of ((1 2), [1])) in S3 X Z2.

Do I use the given as H (the subgroup) and find right cosets for just (1 2) and then coset for [1] separately. Basically I'm just confused on what to do.
 
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FanofAFan said:
Compute the right coset of ((1 2), [1])) in S3 X Z2.

Do I use the given as H (the subgroup) and find right cosets for just (1 2) and then coset for [1] separately. Basically I'm just confused on what to do.

The right coset would be the set of all elements {[tex]\alpha[/tex]} such that [tex]\alpha[/tex]=((1 2),[1])(p,n) where p is an element of S3 and n is an element of Z2. I would list the elements of S3 X Z2 (which would be like ((1 2 3),[2]),((1 2 3),[2])...- there should be 12 elements I believe?), and operate ((1 2), [1]) with each of them. Then those elements are the elements of the right coset of ((1 2),[1]).

Right? I'm just a group theory student myself... but that's how I would go about that.
 
The question doesn't make sense to me. Isn't ((1 2), [1]) just an element of S3xZ2, not a subgroup? Is the question referring to the subgroup generated by that element?
 
The question is referring to ((12), [1]) being the subgroup... I don't really know how to explain it further... hence the confusion.

@sephy, I worked it out the way you explain it
 
Last edited:
It's no surprise you're confused then. You should ask your instructor for clarification.
 
vela said:
The question doesn't make sense to me. Isn't ((1 2), [1]) just an element of S3xZ2, not a subgroup? Is the question referring to the subgroup generated by that element?


The element is its own inverse, so the subgroup generated by that element would just be itself and the identity element. Maybe you are meant to assume that?

Either that or the word "coset" is being mis-used- vela's right, it's not a coset unless it's made with a subgroup. Without the identity ((1 2), [1]) is just a subset of S3xZ2. You could still compute the elements of Ha, but Ha would not technically be considered a coset.
 

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