(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A bowl contains 10 chips: 6 red chips and 4 blue chips. three chips are drawn at random and without replacement. Compute the conditional probability that

a) 2 are red and one is blue;given that at least 1 red chip is among the 3 selected

b) all are red,given that at least 2 red chips are in the sample of 3 chips.

2. Relevant equations

a)

A= red B= blue

3. The attempt at a solution

P(AlB)= 6/10 * 5/9 * 4/8 = 0.16= 16%.

= P(AlB)= P( A[itex]\bigcap[/itex]B) / P(B)

I don't know how to do it when considering the bold. What changes ? At least one red chip and at least 2 red chips? Or can I just ignore that? I did consider all 6 red chips, so I don't know why they say "given that at least 2 red chips in the sample of 3". Of course it's more than 2, because the bowl has 6 red chips.

1. The problem statement, all variables and given/known data

5 cards are to be drawn successively at random and without replacement from an ordinary deck of 52 playing cards. Find the conditional probability that there are at least 3 aces in the hand, given that there are at least 2 aces.

2. Relevant equations

3. The attempt at a solution

I don't get this. The probability to get 3 when there are only 2 in the deck of playing cards?

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# Compute the conditional probability

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