1. The problem statement, all variables and given/known data A bowl contains 10 chips: 6 red chips and 4 blue chips. three chips are drawn at random and without replacement. Compute the conditional probability that a) 2 are red and one is blue; given that at least 1 red chip is among the 3 selected b) all are red, given that at least 2 red chips are in the sample of 3 chips. 2. Relevant equations a) A= red B= blue 3. The attempt at a solution P(AlB)= 6/10 * 5/9 * 4/8 = 0.16= 16%. = P(AlB)= P( A[itex]\bigcap[/itex]B) / P(B) I don't know how to do it when considering the bold. What changes ? At least one red chip and at least 2 red chips? Or can I just ignore that? I did consider all 6 red chips, so I don't know why they say "given that at least 2 red chips in the sample of 3". Of course it's more than 2, because the bowl has 6 red chips. 1. The problem statement, all variables and given/known data 5 cards are to be drawn successively at random and without replacement from an ordinary deck of 52 playing cards. Find the conditional probability that there are at least 3 aces in the hand, given that there are at least 2 aces. 2. Relevant equations 3. The attempt at a solution I don't get this. The probability to get 3 when there are only 2 in the deck of playing cards?