Computing integrals on the half line

[hunt_mat]

Hi,

In my fluids work I have come to integrals of the type:
<br /> \int_{0}^{\infty}\frac{e^{ikx}}{ak^{2}+bk+c}dk<br />
I was thinking of evaluating this via residue calculus but I can't think of the right contour, any suggestions?

Mat

 

[Some Pig]

Try the punctured disc with boundary $C_{\epsilon}\cup[\epsilon,R]\cup C_R.$

 

[Dickfore]

Notice that \vert e^{i \, k \, x} \vert = e^{-x \, \mathrm{Im}k}. This means that the integral would diverge when we take the circle at infinity on the lower (upper) semicircle for positive (negative) x.

 

[Dickfore]

Notice that the inverse Fourier transform of the Heaviside step function:
<br /> \int_{-\infty}^{\infty}{\frac{d k}{2\pi} \, \theta(k) \, e^{i \, k \, x}} = -\frac{1}{2\pi \, i \, x}, \ \mathrm{Im}x &gt; 0<br />
Thus, we may represent the Heaviside step function as:
<br /> \theta(k) = -\frac{1}{2\pi \, i} \, {d t \, \frac{e^{-i \, k \, t}{t + i \, \eta}}, \ \eta \rightarrow +0<br />

Why do we need it? Because your integral goes to:
<br /> \int_{-\infty}^{\infty}{f(k) \, e^{i \, k \, x} \, \theta(k)}<br />
If you substitute the integral representation for the step function and change the order of integration, you should get:
<br /> -\frac{1}{2\pi \, i} \, \int_{-\infty}^{\infty}{\frac{d t}{t + i \, \eta} \, \int_{-\infty}{\infty}{f(k) \, e^{i \, k \, (x - t)}}}<br />
Now, you may use the residue theorem for the integral over k, but you need to close the contour in different half-planes, depending on whetgher x &gt; t or x &lt; t. The remaining integral over t is again over the whole real line, but , due to the above conditions, should be split into -\infty to x, and from x to \infty]. Then, making a sub

 

[hunt_mat]

I should point out that x\in\mathbb{R}

Dick, can you explain the substitution again, I don't quite get what you're doing here and you still haven't mentioned the contour you're integrating over.