Conceptual Physics Homework Questions

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When a large barge filled with scrap iron is in a canal lock and the iron is thrown overboard, the water level will actually fall. This is because the barge displaces water equal to the weight of the iron while it is onboard, but once the iron is in the water, it only displaces water equal to its volume. The discussion emphasizes the importance of understanding the difference between weight and volume displacement in physics. The conclusion reached is that the water level decreases when the iron is thrown overboard. This highlights the necessity of considering all variables when solving physics problems.
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Homework Statement


A large barge filled with scrap iron is in a canal lock. If the iron is thrown overboard, does the water level at the side of the lock, rise, fall, or remain unchanged?


Homework Equations



None. I like math a lot but this class I'm taking is a prerequisite to college physics. I enjoy the class though because I do believe that the fundamental conceptual understanding this class provides for physics is great.

The Attempt at a Solution



I think the water level will remain unchanged. I draw this conclusion because as the iron is thrown in the water it displaces an amount of water equal to the mass of the iron. But as this happens the boats weight is reduced so it displaces less water because of the decrease in weight. So with all said and done there should be no change.

Thanks for the help.
 
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Think about this. If you have a 10,000 ton volume of incredible dense material only 1 foot cube and it is in a big boat that is able to support it in the water, how much weight of water does it displace? If the same 1 cubit foot of material is put in the water, how much volume of water does it displace? How much does that volume weigh?

Would be results be different if the material was the same volume but 10 times the weight?
 
Ohhh I was on the wrong track. So to answer your questions the dense material on the boat will displace a volume of water equal to its weight. But if the object is put in the water then it will only displace an amount of water equal to its volume. It will displace one cubic foot of water.

If the material was the same volume but ten times the weight then it would displace a larger volume of water on the boat, a volume equal to its weight, but the same volume of water if it was submerged as the less heavy object, one cubic foot.

So the answer to my question is that if the iron was to be thrown over board the height of the water would decrease correct? Because the iron out of the water displaces a volume of water equal to its weight, but in water it displaces a volume of water equal to its volume.
 
Yes, now you've got it. The lesson here is to really think about ALL the variables when solving physical problems.
 
Great thanks for the help!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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