- #61
proculation
- 71
- 0
damn it misses a 0.5 too.
Conceptual Physics: Solving Problems in Math & Science
- Thread starter Dsoto489
- Start date
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Homework Help Overview
The discussion revolves around conceptual physics problems, particularly focusing on motion, acceleration, and the effects of gravity. The original poster expresses difficulty with fundamental concepts after a long absence from math and science, seeking logical steps rather than direct answers.
Discussion Character
- Exploratory, Conceptual clarification, Problem interpretation, Assumption checking
Approaches and Questions Raised
- Participants discuss various physics problems involving acceleration, horizontal and vertical motion, and the influence of gravity. There are attempts to clarify the relationships between velocity and acceleration, as well as the separation of horizontal and vertical components in projectile motion. Questions arise about the correct application of formulas and the assumptions that can be made about initial conditions.
Discussion Status
Participants are actively engaging with the problems, providing hints and guidance without giving direct solutions. There is a recognition of the need to separate horizontal and vertical motion in the analysis. Some participants express confusion about the application of formulas and the interpretation of variables, indicating an ongoing exploration of the concepts involved.
Contextual Notes
The original poster mentions a specific set of problems, indicating a larger set of 20 questions. There is a noted discomfort with rounding values and assumptions about initial velocities, as well as a struggle with understanding the implications of gravity on motion.
- #62
proculation
- 71
- 0
Anyway you have the formula. I drawed it very quickly
- #63
Dsoto489
- 43
- 0
k so i did some computing and ended up with Vo=170.3125
- #64
Dsoto489
- 43
- 0
and D= 41.15
- #65
proculation
- 71
- 0
I mixed up, it's my fault. I will correct my drawing gimme some minutes.
- #66
Dsoto489
- 43
- 0
no worries.
- #67
Dsoto489
- 43
- 0
ok, so I found Veloc of y =2.35m/s and Veloc of x =8m/s
- #68
Dsoto489
- 43
- 0
I have 9.79m tall for the height
- #69
- #70
Dsoto489
- 43
- 0
its cool,
with that drawing, the D of X is 4m methinks
with that drawing, the D of X is 4m methinks
- #71
proculation
- 71
- 0
damn forget that one too.
- #72
proculation
- 71
- 0
Now.
- #73
- #74
proculation
- 71
- 0
I guess if there are people watching this they are laughing haha.
- #75
Dsoto489
- 43
- 0
if i get a 0 in between the parentheses can i multiply it by 1/2
- #76
proculation
- 71
- 0
Dsoto489 said:
zero times 0.5 = zero.
That's why I corrected my mistake... I forgot the K of the integral
- #77
Dsoto489
- 43
- 0
sweet
- #78
Dsoto489
- 43
- 0
d=.06780672
- #79
Dsoto489
- 43
- 0
Thank you for the help, i will try again tomorrow.
- #80
proculation
- 71
- 0
AAh you really want me to get my pencils out to resolve that eh ? :P
- #81
Dsoto489
- 43
- 0
Ok! So after reworking the problem with different numbers this is what i did and the problem i needed to resolve:
A ball rolls off a shelf which is 2.8 meters high. If it leaves the shelf with a horizontal velocity of 6 m/s, calculate the distance from the base of the shelf at which the ball will strike the ground.
first i used Dvert=1/2at^2 so, 2.8=1/2 x 9.81 x t^2 solving for the time- the time it would take the ball to hit the floor. after square rooting it took aprox .75s to fall.
using Dhoriz=volt D=6 x .75 the distance from the base at which the ball will strike the ground is 4.53m!
-There is only one other problem I am unable to resolve...
taking a trip you travel 63mph for 30 min, 22mph for 45 min and stop to eat for 20 min. What is your average speed for the entire trip?
what i keep doing is adding the speeds and averaging them, 63+22+0/3=28.33, this answer is wrong(the computer program for school i am using keeps telling me this) Total time is 95 min=1.55hours, i have tried several different ways and just do not get this problem(it seems easy though!)edit+ 85/1.55 =54.83
If you or someone could show me how to approach these types of problems dealing with different speeds over time that would be great. Thanks again proc!
A ball rolls off a shelf which is 2.8 meters high. If it leaves the shelf with a horizontal velocity of 6 m/s, calculate the distance from the base of the shelf at which the ball will strike the ground.
first i used Dvert=1/2at^2 so, 2.8=1/2 x 9.81 x t^2 solving for the time- the time it would take the ball to hit the floor. after square rooting it took aprox .75s to fall.
using Dhoriz=volt D=6 x .75 the distance from the base at which the ball will strike the ground is 4.53m!
-There is only one other problem I am unable to resolve...
taking a trip you travel 63mph for 30 min, 22mph for 45 min and stop to eat for 20 min. What is your average speed for the entire trip?
what i keep doing is adding the speeds and averaging them, 63+22+0/3=28.33, this answer is wrong(the computer program for school i am using keeps telling me this) Total time is 95 min=1.55hours, i have tried several different ways and just do not get this problem(it seems easy though!)edit+ 85/1.55 =54.83
If you or someone could show me how to approach these types of problems dealing with different speeds over time that would be great. Thanks again proc!
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