Conceptual Question-Capacitance

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Homework Statement


We start with a 2.50 μF capacitor connected to a power supply set to a voltage of 9.30 V. Then we increase the voltage on the power supply by 3.00 V. Now what is its capacitance?

Homework Equations


Q=ΔV*C

The Attempt at a Solution


The answer is 2.5 μF still, but WHY doesn't the capacitance change when the voltage changes?
 
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PlatoDescartes said:
The answer is 2.5 μF still, but WHY doesn't the capacitance change when the voltage changes?
Why do you think it should? If you had a 10 ohm resistor across the power supply would you expect it to become 11 ohms if you increased the voltage?
 
phinds said:
Why do you think it should? If you had a 10 ohm resistor across the power supply would you expect it to become 11 ohms if you increased the voltage?
According to the equation Q=VC, if voltage increases, capacitance should too... I'm missing something here... I apologize!
 
PlatoDescartes said:
According to the equation Q=VC, if voltage increases, capacitance should too... I'm missing something here... I apologize!
Capacitance is not dependent on voltage nor charge though, only material/geometry. Which is why it doesn't change.
 
Q is the charge.

If you increase the voltage (V), the charge increases but the capacitance (C) stays constant.
 

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