- #1
songoku
- 2,288
- 323
- Homework Statement
- Please see below
- Relevant Equations
- det (A - Iλ) = 0
My attempt:
$$
\begin{vmatrix}
1-\lambda & b\\
b & a-\lambda
\end{vmatrix}
=0$$
$$(1-\lambda)(a-\lambda)-b^2=0$$
$$a-\lambda-a\lambda+\lambda^2-b^2=0$$
$$\lambda^2+(-1-a)\lambda +a-b^2=0$$
The value of ##\lambda## will be positive if D < 0, so
$$(-1-a)^2-4(a-b^2)<0$$
$$1+2a+a^2-4a+4b^2<0$$
$$a^2-2a+1+4b^2<0$$
$$(a-1)^2+4b^2<0$$
But the LHS of the inequality is always positive so it is not possible for ##(a-1)^2+4b^2## to be less than 0
Where is my mistake? Thanks
Edit: I just realised my mistake. I will revise my working on post #2