Conditions for a E field to be possible

  • Context: Undergrad 
  • Thread starter Thread starter cutesteph
  • Start date Start date
  • Tags Tags
    Conditions Field
Click For Summary

Discussion Overview

The discussion revolves around the conditions necessary for an electric field \( \vec{E} \) to exist in free space, specifically within the context of electrostatic systems. Participants explore the mathematical criteria that must be satisfied, focusing on the divergence and curl of the electric field.

Discussion Character

  • Technical explanation, Conceptual clarification

Main Points Raised

  • One participant suggests verifying the electric field by checking if \( \nabla \times \vec{E} = 0 \).
  • Another participant states that in free space, \( \nabla \cdot \vec{E} = 0 \) must always hold, while \( \nabla \times \vec{E} = 0 \) is only applicable in electrostatic systems.
  • A participant confirms that their system is indeed electrostatic.
  • Following the confirmation, it is reiterated that the electric field must be irrotational and divergence-free.

Areas of Agreement / Disagreement

Participants generally agree on the conditions that must be satisfied for an electric field in an electrostatic system, specifically the need for the field to be irrotational and divergence-free. However, the initial question regarding the verification process remains open to interpretation.

Contextual Notes

The discussion does not resolve the implications of the conditions in non-electrostatic scenarios, nor does it clarify the specific methods for verifying the electric field's properties beyond the stated mathematical conditions.

cutesteph
Messages
62
Reaction score
0
If I want to verify an electric field E is possible in free space, do I just need to check ∇xE =0?
 
Physics news on Phys.org
In free space what always has to hold is ##\vec{\nabla}\cdot \vec{E} = 0## whereas ##\vec{\nabla}\times \vec{E} = 0## only holds in electrostatic systems. Is your system electrostatic?
 
Yes, the system is electrostatic.
 
Then yes you have to check that the electric field is irrotational. You also have to check that it is divergence-free.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
914
  • · Replies 6 ·
Replies
6
Views
591
  • · Replies 29 ·
Replies
29
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K