Conductance of an interacting quasi one dimensional wire

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SUMMARY

The conductance of a quasi one-dimensional quantum wire is quantized in units of 2e^2/h, even when considering electron-electron interactions. While the traditional Fermi gas and Fermi liquid models do not apply in one-dimensional systems, the concept of 1D bands remains relevant for understanding conductance due to the influence of Fermi liquid leads. The discussion highlights the importance of electron interactions within the wire and suggests that a mean-field approach, such as the Luttinger liquid model, may provide insights into the behavior of interacting electrons.

PREREQUISITES
  • Understanding of quasi one-dimensional quantum wires
  • Familiarity with conductance quantization (2e^2/h)
  • Knowledge of Fermi gas and Fermi liquid theories
  • Basic concepts of electron-electron interactions in condensed matter physics
NEXT STEPS
  • Research the Luttinger liquid model and its implications for one-dimensional systems
  • Explore the phenomenon of the 0.7 structure in quantum wires
  • Study the role of contact resistance in quantum conductance
  • Examine literature on electron interactions in low-dimensional systems
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Physicists, condensed matter researchers, and students interested in quantum conductance and the behavior of electrons in low-dimensional systems.

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Why is it appropriate to discuss the conductance of an interacting quasi one dimensional wire using the method for a 1D fermi gas? We don't have a fermi gas anymore and more importantly we don't have a fermi liquid, as we are in 1D. So why do we still use 1D bands to explain the conductance?
Assuming the electrons are non interacting and spin degenerate, the conductance of a quasi one dimensional quantum wire is quantised in units of 2e^2/h. For small voltages, we simply count how many bands have their bottoms below the chemical potential and multiply this by 2e^2/h. This is due to the electron velocity and 1D density of states cancelling for all energies, when we do the integral over occupied energies for each occupied band.

Now we add electron-electron interactions. We don't have a fermi gas or even liquid now as we are in 1D. I naively thought that as the fermi gas/liquid no longer applies we couldn't rely on the above picture. But it appears that we roughly can. My question is this essentially; why?

I can sort of appreciate that it's a contact resistance so will be determined by the fermi liquid leads. Our wire itself is, as before, meant to be perfectly conducting, so the resistance should be determined by what goes on in the leads. (I'm still a little sketchy on this.) This aside, I still can't get my head around why we still talk about 1D bands and whether they have started to be filled. We don't have a fermi gas anymore and more importantly we don't have a fermi liquid, as we are in 1D. So why do we still use 1D bands to explain the conductance?

As a final remark, there are many cases in the literature, for example the 0.7 structure, where the fact the electrons interact does have some bearing. The possible explanations still talk about the 1D bands and mechanisms describing how they're filled. But we don't have a fermi gas or fermi liquid; why talk about 1D bands? Furthermore, the conductance is now not determined just by the fermi liquid leads, the interactions within the wire must now be taken into account.
 
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Can you refer us to the text (if any) you are getting this from? A little context helps.

I'm not sure about the Fermi liquid part, but do you think the reason you can treat the interacting electrons as a fermi gas is simply that it's a mean-field picture? If it was a weak interaction, that would be appropriate.
 

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