Nichrome Wire Brightness in Series: A Conductivity Homework Problem

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SUMMARY

The discussion centers on the brightness of two nichrome wires, P and Q, connected in series to a battery of emf, V. Wire P has a larger diameter than wire Q, affecting their respective resistances and power dissipation. The brightness is determined by the temperature of the wires, which correlates with the power dissipated when a steady state is achieved. The relationship between power, resistance, and cross-sectional area is crucial for understanding the differences in brightness between the two wires.

PREREQUISITES
  • Understanding of electrical resistance and its dependence on cross-sectional area
  • Knowledge of power dissipation in electrical circuits
  • Familiarity with Ohm's Law and its application in series circuits
  • Basic principles of thermal conductivity and temperature effects on materials
NEXT STEPS
  • Study the relationship between resistance and cross-sectional area in conductors
  • Learn about power dissipation in resistive materials using the formula P = I²R
  • Explore the effects of series versus parallel connections on electrical components
  • Investigate the thermal properties of nichrome wire and its applications in heating elements
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Students studying electrical engineering, physics enthusiasts, and anyone interested in the principles of electrical resistance and thermal conductivity in materials.

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Homework Statement



There are 2 nichrome wires P and Q are connected in series to battery of emf , V .
Both P and Q are of same length bu the diameter of wire P is bigger than that of wire Q . When wire P and Q glow steadily , which one would glow brighter ?

Homework Equations





The Attempt at a Solution



What determines the brightness of the nichome wire ? Is it the temperature(as in when its hotter it glows more) ? Then how is different when the nichrome wires are connected in parallel ?
 
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Yes, the brightness will be determined by the temperature. The temperature will be determined by the power dissipated in the wire when a steady state has been reached.
You need an equation that relates the power in the wire to its resistance, and an equation that relates the resistance of the wire to its cross section.
 


Stonebridge said:
Yes, the brightness will be determined by the temperature. The temperature will be determined by the power dissipated in the wire when a steady state has been reached.
You need an equation that relates the power in the wire to its resistance, and an equation that relates the resistance of the wire to its cross section.

thanks !
 

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